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miv72 [106K]
3 years ago
5

Question:

Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0

Answer:

(c) y = 2x - 5

Step-by-step explanation:

y=2x+y=5

subtract 2x from both sides of the equation

the answer is C

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Find two consecutive integers such that the sum of the greatest integer and twice the lesser integer is 40.​
ziro4ka [17]

Answer:

13 and 14.

Step-by-step explanation:

So we have two consecutive integers.

Let's call the first integer a.

Since the integers are consecutive, the other integer must be (a+1) (one more than the last one).

We know that the sum of the greatest integer (or a+1) and twice the lesser integer (a) is 40. Therefore, we can write the following equation:

(a+1)+2(a)=40

The first term represents the greatest integer. The second term represents 2 times the lesser integer. And together, they equal 40.

Solve for a. Combine like terms:

a+1+2a=40\\3a+1=40

Subtract 1 from both sides. The 1s on the left cancel:

(3a+1)-1=(40)-1\\3a=39

Divide both sides by 3:

\frac{3a}{3}=\frac{39}{3}\\a=13

Therefore, a or the first integer is 13.

And the second integer is 14.

And we can check:

14+2(13)=14+26=40

8 0
4 years ago
Read 2 more answers
Which operation would you do first?
svp [43]

Answer:

Addition +

Step-by-step explanation:

You are correct because according to PEMDAS, you have to do what is inside the parentheses first, which just happens to be addition.

7 0
3 years ago
I promise I will mark as brainiest if a speed of a car increase its average speed in a journey of 200 miles by 5 mile/hour the j
jok3333 [9.3K]

Answer:

\large \boxed{\sf \ \ \ \dfrac{\sqrt{4025}-5}{2}=29.22144... \ \ \ }

Step-by-step explanation:

Hello

<u>Let's note the original speed of the car v</u>

it means that in 1 hour he is going v miles

so to go 200 miles it takes ( in hour)

\dfrac{200}{v}

If the speed of the car is v+5 than to go 200 miles it takes (in hour)

\dfrac{200}{v+5}

and this time is one hour less so we can write

\boxed{\sf \ \ \dfrac{200}{v+5}=\dfrac{200}{v}-1 \ \ }

We can multiply by v(v+5) both parts of the equation so

200v=200(v+5)-v(v+5)\\\\200v=200v+1000-v^2-5v\\\\v^2+5v-1000=0

\Delta=b^2-4ac=5^2+4*1000=4025\\\\ \text{There are potential solutions }\\\\\ \ \ \ \ x_1=\dfrac{-5-\sqrt{4025}}{2}\\\\\ \ \ \ \ x_2=\dfrac{-5+\sqrt{4025}}{2}

Only one is positive and this is is

x_1=\dfrac{\sqrt{4025}-5}{2}=29.22144...

So the original speed is 29.22144... mph

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
each month for 6 months,kelsey completes 5 paintings. How many more paintings does she need to complete before she has completed
Solnce55 [7]
5 painting every 6 months so 5x6=30
38-30=8
3 0
3 years ago
Read 2 more answers
Find the center and radius of circle and graph it <br><br> <img src="https://tex.z-dn.net/?f=%28x-4%29%5E%7B2%7D%20%2B%28%20y%20
sergeinik [125]

Answer:

centre = (4,-2)

radius = 3

Step-by-step explanation:

The centre-radius form of the circle equation is in the format

(x – h)² + (y – k)² = r²,

with the centre being at the point (h, k) and the radius being "r"

Given in the question an expression which can be write as

<h3> (x – 4)² + (y – (-2))² = 3²</h3>

So, by translating we can say that

centre = (4,-2)

and

radius = 3

 

3 0
3 years ago
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