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sleet_krkn [62]
3 years ago
12

Ben rolled a number cube numbered one through six. It landed on an odd number 30 times. What is the probability that it lands on

an odd number on the next roll?
Mathematics
1 answer:
elena55 [62]3 years ago
8 0

Answer:

1 /2

Step-by-step explanation:

Sample space of number cube : (1, 2, 3, 4, 5, 6)

Odd numbers on cube : (1, 3, 5) = 3 odd numbers

Since each roll of number cube is independent, the number of times it has landed between fire does not matter :

Therefore, probability of landing on a odd number is :

P = required outcome / Total possible outcomes

P = 3 / 6

P = 1/2

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Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

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At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

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p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
3 years ago
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Step-by-step explanation:

I just did it the same way the other one went, but tbh don't just listen to me I'm not that smart I just believe it's the answer from my math.

6 0
2 years ago
Read 2 more answers
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