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qwelly [4]
3 years ago
6

Assume that females have pulse rates that are normally distributed with a mean of u = 75.0 beats per minute and a standard devia

tion of sigma = 12.5 beats per minute. If 1 adult female is randomly​ selected, find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.
Mathematics
2 answers:
Elan Coil [88]3 years ago
3 0

Answer:

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 75, \sigma = 12.5

Find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

This is the pvalue of Z when X = 81 subtracted by the pvalue of Z when X = 69.

X = 81

Z = \frac{X - \mu}{\sigma}

Z = \frac{81 - 75}{12.5}

Z = 0.48

Z = 0.48 has a pvalue of 0.6844

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 75}{12.5}

Z = -0.48

Z = -0.48 has a pvalue of 0.3156

0.6844 - 0.3156 = 0.3688

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

aalyn [17]3 years ago
3 0

Answer:

P(69

And we can find this probability with this difference:

P(-0.48

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the pulse rates of a population, and for this case we know the distribution for X is given by:

X \sim N(75,12.5)  

Where \mu=75 and \sigma=12.5

We are interested on this probability

P(69

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(69

And we can find this probability with this difference:

P(-0.48

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