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2 years ago

11

(y-7)^2=2y^2-4y+73 solve for y

1 answer:

masya89 [10]2 years ago

7 0

Answer:

y=-4 or y=-6

Step-by-step explanation:

y^2-14y+49=2y^2-4y+73

y^2+10y+24=0

(y+4)(y+6)=0

y=-4 or y=-6

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Someone help me with this

Alenkasestr [34]

Answer:

70°

Step-by-step explanation:

ABC is the center angle that sees the arc and is twice as angle ADC so the measure of ABC is e × 35 = 70

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3 years ago

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Julie pays for a meal at a restaurant with a $20 bill. Let c represent the cost of the food. The total cost includes a tip that

MAVERICK [17]

(c/5+c)-20 You divide the total cost by five to get the tip. You add that to the cost, and the tip and cost added together is the total cost. Subract that from a $20.00 bill and you have the answer! Hope this helps!

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3 years ago

Find a quadratic polynomial whose sum and and product is -7 and -2

vampirchik [111]

Answer:

<h2>x²+7x-2 = 0</h2>

Step-by-step explanation:

The general form of a quadratic equation with roots a and b is expressed as shown;

x²-(sum of root) x + (product of roots) = 0

x² - (a+b)x + ab = 0 ... 1

Given the sum of roots a+b = -7

Product of roots ab = -2

Substituting this values in equation 1 above wil give;

x²-(-7)x+(-2) = 0

x²+7x-2 = 0

The resulting quadratic polynomial is x²+7x-2 = 0

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2 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

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2 years ago

Explain why a graphical display might be skewed. How<br> do you ensure data isn't skewed?

Ipatiy [6.2K]

Answer: hey mate i have you answer

Step-by-step explanation: Sample Response: If the data is collected in a biased manner, the graph could be skewed. Also, if the number of observations is too small, the graph can be skewed. To ensure the data is not skewed, collect a large representative unbiased sample

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3 years ago

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