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3 years ago

Finding the sum of the measures of the interior angles of a convex nonagon

Mathematics

1 answer:

Tresset [83]3 years ago

6 0

Answer:

7 pie

Step-by-step explanation:

the sum of the interior angles of a nonagon is 1260 degrees.

Now The sum of interior angles of a convex N-sided polygon equals to π(N−2) radians.

In case N=9 (nanogon)

this sum is

π(9−2)=7π (radians)

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What is 6 divied 192 please show work

suter [353]

The problem presented with the word used as "divied" is very tricky and misleading to the point that it might create an understanding.

So we will approach this is in two ways.

If this was meant to be "divided by" then it would look like this:
6 / 192

If this was meant to be "divided to" then it would look like this:
192 / 6

Let us first solve for the first possible problem:
6 / 192 = ?
0.0312

0.0312 would be the answer.

Let us then solve for the second possible problem:
192 / 6 = ?
32 = ?

32 would be the answer.

So 0.0312 and 32 would be two possible answers to this problem.

4 0

3 years ago

Read 2 more answers

Can somebody help me with this pleaseee

AysviL [449]

Answer:

lesser x = -4.73205, so -4.73

greater x = -1.26795, so -1.27

7 0

3 years ago

List Least to Greatest, 2/5, 1/3, 4/9, or 3/4 Please help

Ilya [14]

2/5 1/3 4/9 3/4. that's the answer

6 0

3 years ago

Order the numbers from least to greatest put the lowest number on the left 3/4 2/3 and 3/8

Verdich [7]

Hey there!

$\bold{\frac{3}{4}=0.75}$
$\bold{\frac{2}{3}=0.67}$
$\bold{\frac{3}{8}=0.375}$

$\boxed{\boxed{\bold{Answer:\frac{3}{8}\rightarrow\frac{2}{3}\rightarrow\frac{3}{4}}}}$ $\checkmark$

Good luck on your assignment and enjoy your day!

~ $\bold{LoveYourselfFirst:)}$

6 0

3 years ago

I am having trouble with this relative minimum of this equation.<br>

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$