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timofeeve [1]
3 years ago
7

Which phrase describes the algebraic expression 3 x minus 4?

Mathematics
2 answers:
podryga [215]3 years ago
8 0

WHEN THE IMPOSTOR IS SUS !!!

Step-by-step explanation:

zaharov [31]3 years ago
7 0

Answer:

3x - 4 = -12

Step-by-step explanation:

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2c(u-6)+(u-6) complete the expression
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3 years ago
Your company is considering offering 900 employees the opportunity to transfer to its new headquarters in Ottawa and, as personn
Tresset [83]

Answer:

a) P(100M) = \frac{100C100*1100C800}{1200C900}

b) P(1M) = \frac{100C1*1199C899}{1200C900}

Step-by-step explanation:

Extract information from question:

Manager = M = 100

Factory Workers = FW = 200

Miscellaneous Staff = MS = 900

Total Workers = 1200

Moving Workers = 900

'Combinations' are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations the formula below is used:

nCr=\frac{n!}{r!(n-r)!}

where 'n' is the total number of items

'r' is the number of items being chosen at a time

The '!' is the factorial function which is the product of all integers equal to and less than the given integer.

Combinations can be calculated manually using the formula above or by using the nCr function on a scientific calculator.

Part a)

Combinations of all 100 managers being selected

C = nCr=\frac{n!}{r!(n-r)!}

C(100M) = 100C100

Combinations of 800 of factory workers and miscellaneous staff being selected out of 1100 remaining staff

C = nCr=\frac{n!}{r!(n-r)!}

C(800FW/MS) = 1100C800

Total possible unspecified combinations of 900 staff being selected out of 1200 total staff

C = nCr=\frac{n!}{r!(n-r)!}

C(900M/FW/MS) = 1200C900

Probability of all 100 managers being selected:

P(100M) = \frac{100C100*1100C800}{1200C900}

Part b)

Combinations of 1 out of 100 managers being selected

C = nCr=\frac{n!}{r!(n-r)!}

C(1M) = 100C1

Combinations of 899 of managers, factory workers and miscellaneous staff being selected out of 1199 remaining staff

C = nCr=\frac{n!}{r!(n-r)!}

C(899M/FW/MS) = 1199C899

Total possible unspecified combinations of 900 staff being selected out of 1200 total staff

C = nCr=\frac{n!}{r!(n-r)!}

C(900M/FW/MS) = 1200C900

Probability of being the 1 manager being selected:

P(1M) = \frac{100C1*1199C899}{1200C900}

3 0
3 years ago
Is the point (-3, 2) a solution of x-5y<7x − 5 y < 7? Explain how you know.
Crazy boy [7]

Answer:

  yes, it makes the inequality true

Step-by-step explanation:

Try it and see.

  x - 5y < 7

  -3 -5(2) < 7

  -13 < 7 . . . . . . true

The given point is a solution.

3 0
3 years ago
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