Answer:
Step-by-step explanation:
The slope of straight line PR where P(2,3) and R(5,-1) are two vertices of triangle PQR will be =
Therefore, the slope of the altitude passing through Q(-1,1) will be
{Since, the product of slopes of two perpendicular straight line is -1}
So, equation of the altitude is
where c is a constant.
Now, putting x = -1 and y = 1 in the above equation we get
⇒
Therefore, the equation of the altitude is
(Answer)
Area of a circle is πr².
Therefore we can get the radius of the great circle (and thus the sphere) by doing √(A / <span>π).
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√(28.6 / <span>π) = 3.017 to 3DP.
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Surface area of a sphere is 4πr².
4<span>π(3.017)</span>² = 114.4 to 1DP
Question 3)
Given
The point (1, -5)
The slope m = -5/6
Using the point-slope form of the equation of a line

where
- m is the slope of the line
In our case:
substituting the values m = -5/6 and the point (1, -5) in the point-slope form of the equation of the line



Thus, the point-slope form of the equation of the line is:

Question 4)
Given
The point (-1, 5)
The slope m = -7/2
In our case:
substituting the values m = -7/2 and the point (-1, 5) in the point-slope form of the equation of the line



Thus, the point-slope form of the equation of the line is:

Answer:
621,345
Step-by-step explanation:
Easy Here you goo
Hope this helps. Domain and range are the same for this question.