Answer:
<h2>x= 37</h2>
Step-by-step explanation:
This problem can be solved by applying Pythagoras theorem, since the segment AB is tangent to the circle(meaning that the point A is at 90 degree to the circle)
According to Pythagoras theorem "It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides".
given (as seen from the diagram)
x, hypotenuse= ?
opposite= 12
adjacent= 35
Applying Pythagoras theorem
![hyp^2= opp^2+adj^2\\\\hpy=\sqrt{opp^2+adj^2}](https://tex.z-dn.net/?f=hyp%5E2%3D%20opp%5E2%2Badj%5E2%5C%5C%5C%5Chpy%3D%5Csqrt%7Bopp%5E2%2Badj%5E2%7D)
Substituting our given data and solving for hpy we have
![hyp=\sqrt{12^2+35^2} \\\\hyp=\sqrt{144+1225}\\\\hyp=\sqrt{1369}\\\\hyp= 37](https://tex.z-dn.net/?f=hyp%3D%5Csqrt%7B12%5E2%2B35%5E2%7D%20%5C%5C%5C%5Chyp%3D%5Csqrt%7B144%2B1225%7D%5C%5C%5C%5Chyp%3D%5Csqrt%7B1369%7D%5C%5C%5C%5Chyp%3D%2037)
hence x= 37
Answer:
u didnt give us the information in the right order
Step-by-step explanation:
The answer for you problem is 6
Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
The answer is -1.5. Hope this helps