<h2>
Answer:</h2>
<u>The length is</u><u> 250 meters</u>
<h2>
Step-by-step explanation:</h2>
If we look at the left corner of the diagram we see a scale. According to the scale factor of the map
1 cm :1000 cm
The length of the lap on the map is 25 cm
So (25 × 1000) = 25000 cm
Since
1 meter = 100 centimeter
So the actual length of the lap = 25000 ÷ 100 = 250 meters
Answer:
C 152
Step-by-step explanation:
Beacuse it is. Hope that helps
2x+1=13 x=6 so an ok answer would be: 2x+10=40 x=15
Answer:
the answer is c) 182.25
Step-by-step explanation:
The information provided gives you a scale that will ultimately allow you to determine the height of the larger cylinder.
Since it tells us the two are similar, we can use the scale to solve for the second height.
Set up your math like this:
h represents the height you are trying to find.
using a common multiple, you can solve for h.
16 times 4 is 64. so 729 divided by 4 is 182.25
Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
