What's the greatest common factors of 55 and 77?

1 answer:

6 0

The factors of 55 are 1, 5, 11, and 55 .

The factors of 77 are 1, 7, 11, and 77 .

The factors that are common to both numbers are 1 and 11 .

The greatest one is <em>11</em> .

You asked for the "greatest", so you only get one of them. If there were
more than one greatest, then you'd want to know which greatest was
greater than the other greatest.

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Answer:

Step-by-step explanation:

$a_1=S_1=3\cdot1^2+4\cdot1=3+4=7$

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3 years ago

Three to the power of three minus seven plus ten

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Answer:

Step-by-step explanation:

You’re correct

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2 years ago

Read 2 more answers

DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . DG=5 cm and BD=12 cm.

jonny [76]

Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.

Given that </span><span>DG = 5 cm and BD = 12 cm, then

$BG= \sqrt{DG^2+BD^2} \\ \\ = \sqrt{5^2+12^2} = \sqrt{25+144} \\ \\ = \sqrt{169} =13$

Since AG = BG = CG, therefore, CG = 13 cm.</span>

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2 years ago

14x⁴+35x² factor out the GCF

enot [183]

Step 1. Find the Greatest Common Factor (GCF)

GCF = 7x^2

Step 2. Factor out the GCF (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

7x^2(14x^4/7x^2 + 35x^2/7x^2)

Step 3. Simplify each term in parentheses

7x^2(2x^2 + 5)

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2 years ago