Answer:
1+6i
Step-by-step explanation:
Given:
f(x)=x^4 - 2x^3 + 38x^2 - 2 + 37
zero of f(x) = 1-6i
another zero of function = ?
Conjugate Zero theorem:
As per conjugate zero theorem, if a function f(x) has real coefficients and one of zero is a complex number then the conjugate of that complex number will also be a zero of that function i.e. complex zeroes will occur in complex conjugate pairs.
conjugate of 1-6i is 1+6i
hence another zero of f(x) will be 1+6i !
always put the 1st number you would like to turn to scientific notation
so the 1st number here is 3
then you turn 8 into a decimal because it is the only other number that isnt 0 and then it is 3.8
you then count every number after 3 including 8 which is
then you always put 10 x whatever number you are doing but right now it is 3.8
and the answer is
10 x 3.8^7
I dont know anything about the 5 step problem solving plan...
but ur equation is : y = 6x...where y is total saved and x is number of weeks.
when she has a total of 60 bucks....so y = 60
60 = 6x
60/6 = x
10 = x....so it would take her 10 weeks <==
4x +9
3x and x are like terms
And 2 and 7 are like terms
Hope this helps :D
Answer:
The expression equal to 2x^(2)+8 is:
First option (2x-4i)(x+2i)
Step-by-step explanation:
If we multiply
(2x-4i)(x+2i)=(2x)(x)+(2x)(2i)-(4i)(x)-4i(2i)
(2x-4i)(x+2i)=2x^(1+1)+4xi-4xi-8i^(1+1)
Simplifying:
(2x-4i)(x+2i)=2x^2-8i^2
and i^2=-1, then:
(2x-4i)(x+2i)=2x^2-8(-1)
Multiplying:
(2x-4i)(x+2i)=2x^2+8
