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2 years ago

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Triangle EFG is proportional to triangle EHI. The length of side EF is 5 in., the length of side FH is 3 in., and the length of

side HL is 10 in.
What is the area of triangle EFG?

1 answer:

SVETLANKA909090 [29]2 years ago

5 0

Answer:

I don't see the file with it

Step-by-step explanation:

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The power, P (watts) , of a car engine is proportional to the square of its speed, s ( m / s ) . When s = 30 , P = 1260 . Work o

Lapatulllka [165]

Answer:

875 Watts

Step-by-step explanation:

Given that :

P α s²

P = ks²

Where k is the proportionality constant

When ; p = 1260 ; s = 30

1260 = k * 30²

1260 = 900k

k = 1260 / 900

k = 1.4

Value of p ; when s = 25

P = 1.4 * s²

P = 1.4 * 25²

P = 1.4 * 625

P = 875 watt

6 0

3 years ago

Find the missing length indicated<br> i will give brainliest to first correct answer

Ierofanga [76]

Answer:

B) I think

Step-by-step explanation:

3 0

3 years ago

Please answer this correctly

motikmotik

Answer:

$50\%, \: 40\%, \: 10\%$

Step-by-step explanation:

$150:120:30$

$5:4:1$

$\frac{100}{5+4+1}$

$=\frac{100}{10}$

$=10$

$5 \times 10:4\times 10:1\times 10$

$50:40:10$

5 0

3 years ago

Read 2 more answers

Maths equation please help

IrinaVladis [17]

Answer:

<em>V=120cm³</em>

Step-by-step explanation:

<em>v=12(5)(6)-4(10)(6)</em>

<em>v=120cm³</em>

<em>hope it helps...</em>

<em>have a great day!!</em>

7 0

3 years ago

Please help me under stand this question.

Marizza181 [45]

Answer: $2^{30}$

Step-by-step explanation:

In order to solve this exercise it is important to remember:

1. The Negative exponent rule, which states that:

$a^{-n}=\frac{1}{a^n}$

2. The Product of powers property, which states that:

$(a^m)(a^n)=a^{(m+n)}$

Therefore, knowing the explained above and having the following expression provided in the exercise:

$\frac{2^{14}}{2^{-16}}$

You can identify that the numerator and the denominator have the same base 2. Then, you can simplify the expresssion as following:

$(2^{14})(2^{16})=2^{(14+16)}=2^{30}$

7 0

4 years ago