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3 years ago

Find the area for this problem

Mathematics

1 answer:

Stolb23 [73]3 years ago

7 0

Answer:

45.5

Step-by-step explanation:

7*18/2-(18-13)*7/2

63-17.5=45.5

or 13*7/2=45.5

sjdsjfhsjg ;2

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George borrowed $300 from a family member. He told the family member he would pay $50 each month for 6 months to pay it all back

ohaa [14]

The answer is a because im smart

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2 years ago

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the perimeter of a rectangle is 60 meters. if the length of the rectangle is 14 meters. what is the width of the rectangle.,

Ray Of Light [21]

Perimeter is 2width+2length
Therefore since you already know that the perimeter is 60 and the length is 14 you can set up the equation;
60= 2w+14
with this you then need to find w so;
60=2w+14
-14 -14
46=2w
(46/2)=(2w/2)
13=w
The width is 13

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3 years ago

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What is the area of a garden that measures 4mx4mx6mx4mx10mx8m

topjm [15]

The area of the garden is 120 square metre

<h2>Explanation:</h2>

The picture of the garden is shown below. In this problem, we have:

One square
Two rectangles

Recall that the area of a square is given by:

$A_{s}=L^2 \\ \\ A_{s}:Area \ of \ a \ square \\ L:Side \ of \ the \ square$

On the other hand, the area of a rectangle is given by:

$A_{r}=L_{1}\times L_{2} \\ \\ \\ A_{r}:Area \ of \ a \ rectangle \\ \\ L_{1}:Side \ 1 \ of \ the \ rectangle \\ \\ L_{2}:Side \ 2 \ of \ the \ rectangle$

Therefore:

FOR THE SQUARE:

$L=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{s}=4^2 \\ \\ \boxed{A_{s}=16m^2}$

FOR THE RECTANGLE 1:

$L_{1}=6m \\ L_{2}=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{1}}=6(4) \\ \\ \boxed{A_{r_{1}}=24m^2}$

FOR THE RECTANGLE 2:

$L_{1}=10m \\ L_{2}=8m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{2}}=10(8) \\ \\ \boxed{A_{r_{2}}=80m^2}$

Finally, the area of a garden is the sum of the three areas:

$A_{total}=A_{s}+A_{r_{1}}+A_{r_{2}} \\ \\ A_{total}=16m^2+24m^2+80m^2 \\ \\ A_{total}=16+24+80 \\ \\ \boxed{A_{total}=120m^2}$

<h2>Learn more:</h2>

Area of a pizza: brainly.com/question/12878495

#LearnWithBrainly

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2 years ago

What is the scale factor in the dilation ?<br><br>1/6<br><br>1/3<br><br>3<br><br>6

anzhelika [568]

Answer:

Step-by-step explanation:

<u>1) Find two corresponding lengths between the image and the pre-image</u>

Pre-image (bottom side) = 3 units

Image (bottom side) = 9 units

We can use any corresponding lengths for this step.

<u>2) Divide the length of the side from the image by the length of the side from the pre-image</u>

9 units ÷ 3 units

= 3

Therefore, the scale factor of the dilation is 3.

I hope this helps!

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The measure of one angle is six more than half the measure of another angle. If the angles are complementary, find both measures

Snowcat [4.5K]

Answer:

The measures of the two angles are 34° and 56°

Step-by-step explanation:

* Lets explain how to solve the problem

- The complementary angles are the angles whose the sum

of their measures is 90°

- The measure of one angle is six more than half the measure

of another angle

- Let the measure of the second angle angle is x

∵ The measure of the 2nd angle is x

∵ The measure of the first angle is 6 more than the half of the

measure of the second angle

∴ The 1st angle is 6 + 1/2 x

∵ The two angles are complementary

∴ The sum of their measures is 90°

∴ x + (6 + 1/2 x) = 90

∴ (x + 1/2 x) + 6 = 90

∴ 3/2 x + 6 = 90

- Subtract 6 from both sides

∴ 3/2 x = 84

- Multiply both sides by

∴ 3x = 168

- Divide both sides by 3

∴ x = 56

∵ x is the measure of the 2nd angle

∴ The measure of the 2nd angle is 56°

∵ The measure of the 1st angle = 6 + 1/2 x

∵ x = 56

∴ The measure of the 1st angle = 6 + 1/2(56) = 34°

* The measures of the two angles are 34° and 56°

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2 years ago