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Bike > ________300km_________< Van
20km/h 80km/h
In one hour, the bike will have moved 20km and the van would have moved 80km.
The distance between them was 300km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.
300km-(20km+80km) = 200km
So now the distance between them is 200km.
Now another hour passes. The distance between them was 200km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.
200km-(20km+80km) = 100km
So now the distance between them is 100km
Now another hour passes. The distance between them was 100km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.
100km-(20km+80km) = 0km
So now the distance between them is 0km, which means they have met. If we count, it took them 3 hours.
:
Step 1)
Add both speeds. 20km+80km=100km
Step 2)
Total distance between them = 300km
So do 300km/100km = 3hours.
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The solution is: .
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Hope this helped!
, where
is the final velocity in a direction after the acceleration is applied,
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
5320 m/s, the acceleration (the applied by the engine) in x direction is
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then:
0 m/s, the acceleration in y direction is
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: