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Mama L [17]
3 years ago
9

Tools -

Mathematics
1 answer:
rosijanka [135]3 years ago
7 0

Answer:

48

Step-by-step explanation:

You might be interested in
Simplify<br> -4/7+(-4/3)
jasenka [17]

Answer:

40/21

Step-by-step explanation:

-4/7+(-4/3)

common factor is 21

=21/7×-4-21/3×4

=3×-4-7×4 all divided by 21

=-12-28 all divided by 21

=40/21

4 0
3 years ago
Can u plzz help meeee
Strike441 [17]
10 because 8 squares plus 6 squared equals 100 and the root of 100 is ten
6 0
3 years ago
Read 2 more answers
Solve using elimination<br> x+y-2z=8<br> 5x-3y+z=-6<br> -2x-y+4z=-13
Free_Kalibri [48]
So here is your answer with LaTeX issued format interpretation. Full process elucidated briefly, below:

\begin{alignedat}{3}x + y - 2z = 8 \\ 5x - 3y + 2 = - 6 \\ - 2x - y + 4z = - 13 \end{alignedat}

For this equation to get obtained under the impression of those variables we have to eliminate them individually for moving further and simplifying the linear equation with three variables along the axis.

Multiply the equation of x + y - 2z = 8 by a number with a value of 5; Here this becomes; 5x + 5y - 10z = 40; So:

\begin{alignedat}{3}5x + 5y - 10z = 40 \\ 5x - 3y + z = - 6 \\ - 2x - y + 4z = - 13 \end{alignedat}

Pair up the equations in a way to eliminate the provided variable on our side, that is; "x":

5x - 3y + z = - 6

-

5x + 5y - 10z = 40
______________

- 8y + 11z = - 46

Therefore, we are getting.

\begin{alignedat}{3}5x + 5y - 10z = 40 \\ - 8y + 11z = - 46 \\ - 2x - y + 4z = - 13 \end{alignedat}

Multiply the equation of 5x + 5y - 10z = - 40 by a number with a value of 2; Here this becomes; 10x + 10y - 20z = 80.

Multiply the equation of - 2x - y + 4z = - 13 by a number with a value of 5; Here this becomes; - 10x - 5y + 20z = - 65; So:

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 8y + 11z = - 46 \\ - 10x - 5y + 20z = - 65 \end{alignedat}

Pair up the equations in a way to eliminate the provided variables on our side, that is; "x" and "z":

- 10x - 5y + 20z = - 65

+
10x + 10y - 20z = 80
__________________

5y = 15

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 8y + 11z = - 46 \\ 5y = 15 \end{alignedat}

Multiply the equation of - 8y + 11z = - 46 by a number with a value of 5; Here this becomes; - 40y + 55z = - 230.

Multiply the equation of 5y = 15 by a number with a value of 8; Here this becomes; 40y = 120; So:

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 40y + 55z = - 690 \\ 40y = 120 \end{alignedat}

Pair up the equations in a way to eliminate the provided variables on our side, that is; "y":

40y = 120

+

- 40y + 55z = - 230
_________________

55z = - 110

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 40y + 55z = - 230 \\ 55z = - 110 \end{alignedat}

Solving for the variable of 'z':

\mathsf{55z = - 110}

\bf{\dfrac{55z}{55} = \dfrac{-110}{55}}

Cancel out the common factor acquired on the numerator and denominator, that is, "55":

z = - \dfrac{\overbrace{\sout{110}}^{2}}{\underbrace{\sout{55}}_{1}}

\boxed{\mathbf{z = - 2}}

Solving for variable "y":

\mathbf{\therefore \quad - 40y - 55 \big(- 2 \big) = - 230}

\mathbf{- 40y - 55 \times 2 = - 230}

\mathbf{- 40y - 110 = - 230}

\mathbf{- 40y - 110 + 110 = - 230 + 110}

Adding the numbered value as 110 into this equation (in previous step).

\mathbf{- 40y = - 120}

Divide by - 40.

\mathbf{\dfrac{- 40y}{- 40} = \dfrac{- 120}{- 40}}

\mathbf{y = \dfrac{- 120}{- 40}}

\boxed{\mathbf{y = 3}}

Solve for variable "x":

\mathbf{10x + 10y - 20z = 80}

\mathbf{Since, \: z = - 2; \quad y = 3}

\mathbf{10x + 10 \times 3 - 20 \times (- 2) = 80}

\mathbf{10x + 10 \times 3 + 20 \times 2 = 80}

\mathbf{10x + 30 + 20 \times 2 = 80}

\mathbf{10x + 30 + 40 = 80}

\mathbf{10x + 70 = 80}

\mathbf{10x + 70 - 70 = 80 - 70}

\mathbf{10x = 10}

Divide by this numbered value \mathbf{10} to get the final value for the variable "x".

\mathbf{\dfrac{10x}{10} = \dfrac{10}{10}}

The numbered values in the numerator and the denominator are the same, on both the sides. This will mean the "x" variable will be left on the left hand side and numbered values "10" will give a product of "1" after the division is done. On the right hand side the numbered values get divided to obtain the final solution for final system of equation for variable "x" as "1".

\boxed{\mathbf{x = 1}}

Final solutions for the respective variables in the form of " (x, y, z) " is:

\boxed{\mathbf{\underline{\Bigg(1, \: \: 3, \: \: - 2 \Bigg)}}}

Hope it helps.
8 0
3 years ago
Read 2 more answers
Can anyone help please?
Korolek [52]

Answer:

6

Step-by-step explanation:

6(2) = 12

12 + 9 = 21

21/3 = 7

7 - 1 = 6 <--- Number that's she's thinking

I tested every number!

8 0
3 years ago
Read 2 more answers
Explain using words or drawings how to to write 6/9 in simplest form
Neporo4naja [7]
To reduce down a fraction you can try to find factors that go in both the numerator (top # of fraction) and denominator (bottom #)

So, for 6/9, 3 goes in both of them. When you divide each number by 3 you get:

2/3
7 0
4 years ago
Read 2 more answers
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