Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:
11
Step-by-step explanation:
56.50-7=49.50
49.50divided by 4.50=11
Answer:
∠C (Interior) =78°
∠B (Interior) = 62°
Step-by-step explanation:
Given:
∠A (Interior) = 40°
∠C (exterior) = 102°
Computation:
∠C (Interior) = 180° - 102°
∠C (Interior) =78°
∠B (Interior) = 180° - ∠A (Interior) - ∠C (Interior)
∠B (Interior) = 180° - 78° - 40°
∠B (Interior) = 180° - 118°
∠B (Interior) = 62°
Answer: 23.80
Step-by-step explanation:
166
I guess you just subtract the numbers
297-131=
Or there is something am I missing on here
