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N76 [4]
2 years ago
11

Jason has 39 cards and Mitch as 51 cards. The total number of cards that the boys have is 3 times the number of cards that Steve

has. How many cards does Steve have?
Mathematics
1 answer:
icang [17]2 years ago
4 0
Steve has 30 cards if you add 39 and 51 in the divided by three you will get 30 which is the amount of cards Steve has
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What is the length of the hypotenuse of the triangle below
Hatshy [7]
One way to solve this is to use Pythagorean theorem: the square of one leg of triangle plus square of other leg of the triangle equals c the hypotenuse (longest side of triangle). You might see this as the formula a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse.
In this case, the legs are 3√2 and the hypotenuse is h.
Using the formula:
(3√2)² + (3√2)² = h²
18 + 18 = h²
h = 6

The other way to do this is with trigonometric angles.
Remember cosine is adjacent over hypotenuse.
cos(45°) = (3√2) / h
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4 0
3 years ago
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Area triangles? it says show work so pls do
coldgirl [10]

\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2} \times (30 \times h) \\  \\  \leadsto \frac{1}{2}   \times 30h \\  \\  \leadsto  \frac{1}{ \cancel{2}} \times  \cancel{30}h \\  \\  \leadsto1 \times 15h \\  \\  \leadsto \: h = 15 \: yd

Therefore, the require height is 15 yd.

\green\starProof:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2}  \times (30 \times 15) \\  \\  \leadsto \frac{1}{ \cancel{2}}   \times  \cancel{450} \\  \\  \leadsto1 \times 225  \\  \\  area = 225  {yd}^{2}

\boxed{ \frak \red{brainlysamurai}}

6 0
1 year ago
NEED HELP!!! please:)
Dahasolnce [82]
No, Jonah is not correct. The answer is shown in the picture.

8 0
2 years ago
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kherson [118]
Probably 5 because it only states 1 firework
5 0
3 years ago
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Simplify the expression.
spayn [35]

Answer:

C. \huge\frac{1}{3x {y}^{2}  {z}^{4}}

Step-by-step explanation:

(9 {x}^{2}  {y}^{4}  {z}^{8} )^{  - \frac{1}{2} }  \\   \\  = ( {3}^{2}  {x}^{2}  {y}^{4}  {z}^{8} )^{  - \frac{1}{2} }  \\  \\  =  \frac{1}{( {3}^{2}  {x}^{2}  {y}^{4}  {z}^{8} )^{ \frac{1}{2} }}  \\  \\  =  \frac{1}{(3x {y}^{2}  {z}^{4})^{2 \times  \frac{1}{2} }  }  \\  \\  =  \frac{1}{3x {y}^{2}  {z}^{4}} \\  \\  \red{ \bold{ \therefore \: (9 {x}^{2}  {y}^{4}  {z}^{8} )^{  - \frac{1}{2} } =  \frac{1}{3x {y}^{2}  {z}^{4}} }}\\

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