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jeyben [28]
3 years ago
5

Given the algebraic representation of a linear transformation (x,y) (3x-4, 1/5y-2),what trasformations are occuring

Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Answer:

We can define the algebraic transformations used here as:

Horizontal translation.

For a general point (x, y), a horizontal translation of N units is written as:

(x + N, y)

if N < 0, the translation is to the left

if N > 0, the translation is to the right.

Vertical translation:

For a general point (x, y), a vertical translation of N units is written as:

(x , y + N)

If N < 0, the translation is downwards

if N > 0, the translation is upwards.

Vertical dilation:

For a point (x, y), a vertical dilation of scale factor k is given by:

(y, k*y)

Horizontal dilation:

A dilation of scale factor k is written as:

(x/k, y)

Here we go from:

(x, y) to (3x - 4, (1/5)*y - 2)

So we have:

An horizontal dilation of scale factor 1/3 followed of a horizontal translation of 4 units.

And a vertical dilation of scale factor (1/5) followed by a translation downwards of 2 units.

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6x + 15xy<br> Looking For Factor
padilas [110]

Answer:

x(6 + 15y)

Step-by-step explanation:

In this instance, you can divide by a factor of x.

6x/x = 6

15xy/x = 15y

Therefore, we are left with 6 + 15y.

6 0
3 years ago
The pH level of a solution measures how acidic or basic the solution is. Values between 0 and 7 are considered acidic while valu
Furkat [3]

Answer:

  about 2.47

Step-by-step explanation:

Your calculator will tell you ...

  -\log{(3.4\times 10^{-3})}\approx 2.4685\approx\bf{2.47}

4 0
3 years ago
G(x) = -2x^3 – 15x^2 + 36x
shusha [124]

Consider the function G(x) = -2x^3 - 15x^2 + 36x. First, factor it:

G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).

The x-intercepts are at points \left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).

1. From the attached graph you can see that

  • function is positive for x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);
  • function is negative for x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).

2. Since

G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x) the function is neither even nor odd.

3. The domain is x\in (-\infty,\infty), the range is y\in (-\infty,\infty).

8 0
4 years ago
Read 2 more answers
PLEASE HELP!! 25 POINTS!! REALLY!!!
Snezhnost [94]
Reflex angle.
hope this helped!
3 0
3 years ago
Read 2 more answers
Round inglés
Andrew [12]

Answer:

13. 200

14. 8,300

15. 500

16. 2,500

Step-by-step explanation:

13. It is more than 4

14. It is more than 4

15. It is less than 4

16. It is more than 4

5 0
3 years ago
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