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ra1l [238]
3 years ago
9

Help and make sure its right

Mathematics
1 answer:
svetlana [45]3 years ago
7 0

Answer:

(3,3)

Step-by-step explanation:

The solution to this graph is always where the two lines intersect.

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please help! Triangle PQR is in a coordinate plane. The triangle is reflected across the y–axis and then translated 11 units lef
Maurinko [17]

Step-by-step explanation:

Triangle PQR is in a coordinate plane. The triangle is reflected across the y–axis and

then translated 11 units left to form Triangle P'Q'R'. Determine which of the following statements must be true regarding this transformation. Select True or False for each statement.

Angle P has the same measure as angle P'. T or F

Angle Q has the same measure as angle R'. T or F

Angle R has the same measure as angle R'. T or F

IF RIGHT PLZ GIVE BRAINLIEST  

THANK U  

HAVE A GREAT DAY AND BE SAFE :)

XD

7 0
3 years ago
Four friends shared 1/2 of one carton of orange juice and 1/4 of another carton of apple juice. What fraction of each carton of
Natalka [10]

Answer:

\dfrac{1}{16}

\dfrac{1}{32}

\dfrac{3}{32}

Step-by-step explanation:

So in the first carton of orange juice 4 friends shared the juice.

This can be shown as:

\dfrac{(\dfrac{1}{2})}{4}

\dfrac{(\dfrac{1}{2})}{4}=\dfrac{1}{16}

The 4 friends got 1/16 of the carton each in the first carton of OJ.

Next for the second carton, it can be shown as:

\dfrac{(\dfrac{1}{4})}{4}

\dfrac{(\dfrac{1}{2})}{4}=\dfrac{1}{32}

The 4 friends got 1/32 of the carton each in the first carton of OJ.

Now to see how much they got in total each, we simply add 1/16 to 1/32

Total OJ each = \dfrac{1}{16}+\dfrac{1}{32}

Total OJ each = \dfrac{3}{32}

Each friend got a total of \dfrac{3}{32} each from both cartons of OJ.

3 0
2 years ago
Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin
Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

ax^2+bx+c=0, a\neq 0

Then to resolve a quadratic equation we apply Bhaskara's formula:

x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}

x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}

It usually has two solutions.

But it could happen that \sqrt{b^2-4ac} then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0
3 years ago
Write an
tensa zangetsu [6.8K]

Answer:

y=-2x+12

Step-by-step explanation:

This is an equation in slope-intercept form:

y=mx+b (where m is the slope and b is the y-intercept)

We are given the slope, -2.

y=-2x+b

We plug in the values (5,2):

2=(-2)*5+b

2=-10+b

b=12

The equation is:

y=-2x+12

3 0
3 years ago
Can someone help me ASAP!!
Mkey [24]
It’s the light blue one!!!
7 0
3 years ago
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