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2 years ago

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Mathematics

1 answer:

atroni [7]2 years ago

6 0

I’m not sure what the answer is , hopefully some ine can help you 66

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Ciaran scores 76% work out 76% of 75 marks Help pls

dlinn [17]

To get 76% of 75 you turn the fraction to a decimal, then multiply it to the number. 76% as a decimal us 0.76 and 0.76 * 75 = 57

So, Ciaran got 57 out of 75 questions right.

3 0

3 years ago

Given a normal distribution with mu equals 100μ=100 and sigma equals 10 commaσ=10, complete parts (a) through (d). loading...

m_a_m_a [10]

I believe the parts are:

A. What is the probability that Upper X greater than 95X>95?

B. What is the probability that Upper X less than 75X<75?

C.What is the probability that Upper X less than 85X<85 and Upper X greater than 125X>125?

D. 95% of the values are between what two X-values (symmetrically distributed around the mean)?

Solution:

We use the equation for z score:

z = (X – μ) / σ

Then use the standard normal probability tables to locate for the value of P at indicated z score value.

A. Z = (95 – 100) / 10 = - 0.5

Using the tables, the probability at z = -0.5 using right tailed test is:

P = 0.6915

B. Z = (75 – 100) / 10 = - 2.5

Using the tables, the probability at z = -2.5 using left tailed test is:

P = 0.0062

C. Z = (85 – 100) / 10 = - 1.5

Using the tables, the probability at z = -2.5 using left tailed test is:

P = 0.0668

Z = (125 – 100) / 10 = 2.5

Using the tables, the probability at z = 2.5 using right tailed test is:

P = 0.0062

So the probability that 85<X and X>125 is:

P(total) = 0.0668 + 0.0062

P(total) = 0.073

D. P(left) = 0.025, Z = -1.96

P(right) = 0.975, Z = 1.96

The X’s are calculated using the formula:

X = σz + μ

At Z = -1.96

X = 10 (-1.96) + 100 = 80.4

At Z = 1.96

X = 10 (1.96) + 100 = 119.6

So 95% of the values are between 80.4 and 119.6 (80.4< X <119.6).

7 0

2 years ago

Katie bought 2 one gallon bottles for a party. Her guest drank 5/4 gallons of juice. What is the fraction of juice leftover? Sho

frosja888 [35]

Answer:

3/4 gallons of juice

Step-by-step explanation:

Katie bought 2 one-gallon bottles for a party.

2 one-gallon bottles = 2-gallon bottles of juice

We are told that:

Her guest drank 5/4 gallons of juice.

The fraction of juice leftover is calculated as:

2 gallons of juice - 5/4 gallons of juice

2 - 5/4

Lowest Common Denominator = 4

2/1 - 5/4

= 8 - 5/4

= 3/4 gallons of juice

Therefore, the fraction of juice leftover is 3/4 gallons of juice

7 0

2 years ago

Simplify (Are all division) 2+4i 3i 3+2i 4+i 2i^11

Alla [95]

$We\ know:\ i=\sqrt{-1}\to i^2=-1$

$\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i$

$\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i$

$2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i$

$Used:\ (a+b)(a-b)=a^2-b^2$

6 0

2 years ago

How to solver for 2y-1/3=5 prove: y= 8

nirvana33 [79]

3×2y-(1/3×3)=5×3
6y-1=15
6y-1+1=15+1
6y=16
y=8/3
Y cannot be 8

3 0

2 years ago