This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
I don’t understand the question, can you restate it?
This is the graph for the equation, it crosses through points (0,-8) (-2,4) (-1.6,0) and its vertex is (-2,2)
Hope this helps !!
If we let 
be the number of pages read in 1 hour, then in 7 hours Doug reads 
pages. We know that this number of pages is 231, so we have
Y=-1/3+2 should be what you are looking for.
