Sometimes, a crackling sound is heard while taking off a sweater during winters. Explain

A potter's wheel is rotating around a vertical axis through its center at a frequency of 2.0 rev/srev/s . The wheel can be consi

vagabundo [1.1K]

Answer:1.7 rev/s

Explanation:

Given

Frequency of wheel $N_1=2\ rev/s$

angular speed $\omega_1=2\pi N_1=4\pi\ rad/s$

mass of wheel $m_1=4.5\ kg$

diameter of wheel $d_1=0.30\ m=30\ cm$

radius of wheel $r_1=\frac{d_1}{2}=\frac{30}{2}=15\ cm$

mass of clay $m_2=2.8\ kg$

the radius of the chunk of clay $r_2=8\ cm$

Moment of inertia of Wheel

$I_1=\dfrac{m_1r_1^2}{2}=\dfrac{4.5\times 15^2}{2}\ kg-cm^2$

Combined moment of inertia of wheel and clay chunk

$I_2=\dfrac{m_1r_1^2}{2}+\dfrac{m_2r_2^2}{2}=\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2}\ kg-cm^2$

Conserving angular momentum

$\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow \dfrac{4.5\times 15^2}{2}\cdot 4\pi=(\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2})\omega_2\\\\\Rightarrow \omega _2=\dfrac{4\pi }{1+\dfrac{2.8}{4.5}\times (\dfrac{8}{15})^2}=\dfrac{4\pi}{1+0.1769}=0.849\times 4\pi$

Common frequency of wheel and chunk of clay is

$\Rightarrow N_2=\dfrac{4\pi \times 0.849}{2\pi}=1.698\approx 1.7\ rev/s$

5 0

3 years ago

My dad gifted me a calculator. I have observed that very small cells are used in a calculator. What are these cells called and w

Morgarella [4.7K]

The cells are called insibatss, I think I spelled that right but

7 0

3 years ago

f1=30Nandf2=10Nact on amass of 2kg if the cofficient of friction between the mass and the horizontal surface is 0.2 what is the

Alexus [3.1K]

The mass is moving with an acceleration of 13.299 m/s².

<h3>What is the straight forward meaning of acceleration?</h3>

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations.

According to therefore mentioned statement,

the direction of the net force applied on an object determines its acceleration;

according to mentioned data;

F₁=30N

F₂=10N

Net force on object;

F=F₁+F₂

F=F₁y+F₂Cos30°(-x)+F₂ Sinx(-y)

F=3y+10×(√3/2)(-x)+10×(1/2)(-y)

F=ma

ma=-5√3/2(x)+25y

2a=-5√3x/2+25y

a=-5√3x+25y

magnitude(a)=√(-5√3/2)²+(25/2)²

(a) =13.299m/s²

to know more about acceleration visit;

brainly.com/question/15295474

#SPJ9

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2 years ago

What does soil structure refer to?

Zigmanuir [339]

A this refers to the make up of the soil

6 0

4 years ago

Read 2 more answers

A spring with a spring constant of 165 N/m is attached to a 2.0 kg mass and set into motion.

marin [14]

Explanation:

We have,

Spring constant of the spring, k = 165 N/m

Mass, m = 2 kg

It is required to find the period of the mass-spring system. For the spring mass system, the period is given by :

$T=2\pi \sqrt{\dfrac{m}{k} }\\\\T=2\pi \sqrt{\dfrac{2}{165} }\\\\T=0.69\ s$

The frequency of vibration is reciprocal of its time period. So,

$f=\dfrac{1}{T}\\\\f=\dfrac{1}{0.69}\\\\f=1.44\ Hz$

So, the period of the mass-spring system is 0.69 s and frequency is 1.44 Hz.

3 0

4 years ago