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alexira [117]
3 years ago
11

In September, a greeting card company's total profit was 22% less than it was in august. The total profit for the two months was

$689,000. find the profit for each month
Mathematics
1 answer:
Trava [24]3 years ago
5 0
Profit for August: x
Profit for September: x - 22%x
Total Profit for August & September: $689,000

x + x - 22% x = 689,000

2x - .22x = 689,000
1.78x = 689,000
x = 689,000/1.78
x = 387,078.65

August Profits: $387,078.65
September Profits: 387,078.65 - (22%)(387,078.65) = 387,078.65 - 85,157.30 = 301,921.35

August Profits: $387,078.65

September Profits
$301,921.35
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Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of
suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}

The values of the cummulative function of the standard normal variable W, which we will denote \phi are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf
4 0
3 years ago
Last Tasha a 90 fries in 18 minutes find her fry eating right and fries per minute
ollegr [7]

Answer:

5

Step-by-step explanation:

90 fries in 18 minutes. You would divide 90 by 18 to get the answer of 5 fries per minute.

6 0
2 years ago
Help me, please !!!!!
vova2212 [387]

Answer: 100

Hi!

ok so the Pythagorean theorem is

c=\sqrt{x} a^2+b^2=\sqrt{x} 8^2+6^2=10

so the other side is 10.

the square 8 is 8*8

and square 6 is 6*6

so the other square is 10*10=100.

so the area of the blank square is 100.

Step-by-step explanation:

Can I have brainliest?

Thanks!

Have a nice day!

4 0
3 years ago
PLEASE HELP
horrorfan [7]

Answer:

C(2, 2) is the solution to both lines A and B.

Step-by-step explanation:

Line A is given as:

A straight line labeled A joins the ordered pair 3, 0 and the ordered pair 0, 6.

We know that the equation of a line passing through (a,b) and (c,d) is calculated as:

Hence, the equation of line is:

Hence, equation of line A is:

Similarly B is a line passing through (0,0) and (5,5).

Hence, the equation of line B is:

So, from the graph we observe that, the point of intersection of the two lines is (2,2).

Thus, option C is correct.

8 0
2 years ago
1. The number of rabbits on an island is increasing exponentially.
Zina [86]

Answer:

<em>There are approximately 114 rabbits in the year 10</em>

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

P=P_o(1+r)^t

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

We are given two measurements of the population of rabbits on an island.

In year 1, there are 50 rabbits. This is the point (1,50)

In year 5, there are 72 rabbits. This is the point (5,72)

Substituting in the general model, we have:

50=P_o(1+r)^1

50=P_o(1+r)\qquad\qquad[1]

72=P_o(1+r)^5\qquad\qquad[2]

Dividing [2] by [1]:

\displaystyle \frac{72}{50}=(1+r)^{5-1}=(1+r)^{4}

Solving for r:

\displaystyle r=\sqrt[4]{\frac{72}{50}}-1

Calculating:

r=0.095445

From [1], solve for Po:

\displaystyle P_o=\frac{72}{(1+r)^5}

\displaystyle P_o=\frac{72}{(1.095445)^5}

P_o=45.64355

The model can be written now as:

P=45.64355(1.095445)^t

In year t=10, the population of rabbits is:

P=45.64355(1.095445)^{10}

P = 113.6

P\approx 114

There are approximately 114 rabbits in the year 10

5 0
3 years ago
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