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2 years ago

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Endpoint given the Midpoint: * The midpoint of RP is M(2, 4). If one of the end points is R(-1,7), find the coordinates of the o

ther end point.

1 answer:

marin [14]2 years ago

8 0

Answer:

The coordinates of other point are: (5,1)

Step-by-step explanation:

Given coordinates are:

M(x,y) = (2,4)

R(x_1,x_2) = (-1,7)

We have to find the coordinates of other point (x2,y2)

The formula for mid-point is given by:

$M(x,y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Putting the values we get

$(2,4) = (\frac{-1+x_2}{2}, \frac{7+y_2}{2})$

Putting respective elements equal

$\frac{-1+x_2}{2} = 2\\-1+x_2 = 2*2\\-1+x_2 = 4\\x_2 = 4+1\\x_2 = 5\\And\\\frac{7+y_2}{2} = 4\\7+y_2 = 4*2\\7+y_2 = 8\\y_2 = 8-7\\y_2 = 1$

Hence,

The coordinates of other point are: (5,1)

You might be interested in

Dana draws a triangle with one angle that has a measure of 40∘.

OLEGan [10]

Answer:

140°

Step-by-step explanation:

<u>Given:</u>

Dana draws a triangle with one angle that has a measure of 40∘.

<u>Question asked:</u>

What is the measure of the angle’s adjacent exterior angle?

Solution:

<u>As we know:</u>

<u><em>Sum of the adjacent interior and exterior angles is 180°.</em></u>

Interior angle = 40°

Adjacent exterior angle = ?

Interior angle + Adjacent exterior angle = 180°

40° + Adjacent exterior angle = 180°

<u>By subtracting both sides by 40°</u>

40° - 40° + Adjacent exterior angle = 180° - 40°

Adjacent exterior angle = 140°

Therefore, the measure of the angle’s adjacent exterior angle will be 140°.

4 0

3 years ago

For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:

Oksi-84 [34.3K]

The half-range sine series is the expansion for $f(t)$ with the assumption that $f(t)$ is considered to be an odd function over its full range, $-1$ . So for (a), you're essentially finding the full range expansion of the function

$f(t)=\begin{cases}2-t&\text{for }0\le t$

with period 2 so that $f(t)=f(t+2n)$ for $|t|$ and integers $n$ .

Now, since $f(t)$ is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

$f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L$

where

$b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt$

In this case, $L=1$ , so

$b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt$
$b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{4-2(-1)^n}{n\pi}$

The half-range sine series expansion for $f(t)$ is then

$f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t$

which can be further simplified by considering the even/odd cases of $n$ , but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming $f(t)$ is even/symmetric across its full range. In other words, you are finding the full range series expansion for

$f(t)=\begin{cases}2-t&\text{for }0\le t$

Now the sine series expansion vanishes, leaving you with

$f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L$

where

$a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt$

for $n\ge0$ . Again, $L=1$ . You should find that

$a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3$

$a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt$
$a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}$
$a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}$

Here, splitting into even/odd cases actually reduces this further. Notice that when $n$ is even, the expression above simplifies to

$a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0$

while for odd $n$ , you have

$a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}$

So the half-range cosine series expansion would be

$f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t$
$f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t$
$f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t$

Attached are plots of the first few terms of each series overlaid onto plots of $f(t)$ . In the half-range sine series (right), I use $n=10$ terms, and in the half-range cosine series (left), I use $k=2$ or $n=2(2)-1=3$ terms. (It's a bit more difficult to distinguish $f(t)$ from the latter because the cosine series converges so much faster.)

5 0

3 years ago

A cruise left port A and traveled towards port B 225 km away. After 1.5 hours of travel, the cruise was stopped for a half an ho

Softa [21]

Answer:

50

Step-by-step explanation:

v = the original speed of the cruise

d = 225 km the distance passed

t = d/v = 225/v the total time of the travel

v*1.5 + (v + 10)(d/v - 1.5 - 0.5) = d (using the formula distance = speed*time)

1.5v + (v + 10)(225/v - 2) = 225

Look at the images to see the solved equation

7 0

3 years ago

A survey showed that 35% of the students prefer plain white milk over chocolate milk. If the school has 1200 students. How many

Pani-rosa [81]

780 students prefer chocolate milk.

Step-by-step explanation:

Let,

the total percentage = 100%

Students who prefer plain white milk = 35%

Students who prefer chocolate milk = 100 - 35 = 65%

Number of students = 1200

No. of students who prefer chocolate milk = 65% of total students

No. of students who prefer chocolate milk = $\frac{65}{100}*1200$

No. of students who prefer chocolate milk = $\frac{78000}{100}\\$

No. of students who prefer chocolate milk = 780

780 students prefer chocolate milk.

Keywords: percentage, subtraction

Learn more about subtraction at:

#LearnwithBrainly

4 0

3 years ago

What is 0.7, 7/9, 7/8 in order from greatest to least

Sphinxa [80]

Simple...

change them all into fractions or decimals...

0.7---> 0.7

$\frac{7}{9}$ -->>0.77

$\frac{7}{8}$ --->>0.875

Ordering from greatest to least....

0.875-->>0.77-->>0.7

$\frac{7}{8}$ -->> $\frac{7}{9}$ -->>0.7

Thud, your answer.

5 0

3 years ago