I think that since their is no = sign you can’t have just one nimber because you can’t fully simplify... I got 4c-12
First, some housekeeping:
cos = 12/13 is incomplete; "cos" must have an argument (input).
cos x = 12/13 is fine; here "cos" has the argument (input) x.
Given that cos x = 12/13, find sin x. To do this, we'll need to find the length of the opposite side, given that the hypo length is 13 and the adj. side length is 12.
12^2 + opp^2 = 13^2, or opp^2 = 169-144 = 25.
Then the opp side could be either 5 or -5. Let's assume that it's +5, and that angle x is in the first quadrant.
Then sin x = opp / hyp = 5/13 (answer)
cos 2 is an entirely different kind of problem. Here you are told what the argument (input) to the cosine function is (it is 2, which here means 2 radians).
Using a calculator: cos 2 = -0.416. Note that the angle 2 rad is in QII, which is why the "adjacent side" is negative and also why the cos of 2 is negative.
Answer:
a) x^2 + y^2
b) 9-xy
Step-by-step explanation:
Here, we want to write the algebraic statements as expressions;
a) The sum of the squares of x and y
The square of x is x^2
The square of y is y^2
The sum of the squares is x^2 + y^2
ii) Product of x and y subtracted from 9
The product of x and y is x * y = xy
Subtracting these from 9, we have;
9-xy
