Answer:
h, j2, f, g, j1, i, k, l (ell)
Step-by-step explanation:
The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).
We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).
The horizontal asymptotes are ...
- h(x): 16x/(-4x) = -4
- j1(x): 2x^2/x^2 = 2
- i(x): 3x/x = 3
- l(x): 15x/(2x) = 7.5
- g(x): x^2/x^2 = 1
- j2(x): 3x^2/-x^2 = -3
- f(x): 0x^2/(12x^2) = 0
- k(x): 5x^2/x^2 = 5
So, the ordering least-to-greatest is ...
h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)
The area of a triangle is 1/2 x base x height.
The area of the triangle is 1/2 x 6 x 8 = 24 square cm.
There are 4 identical triangles so 24 x 4 = 96 square cm.
The area of the square base = 6 x 6 = 36 square cm.
Total area = 96 + 36 = 132 square cm.
Answer:
38=7x-y
Step-by-step explanation:
standard form= Ax+By+C
(y-3=7(x-5))
(y-3=7x-35)+3 to both sides
(y=7x-38) +38 to both sides
(y+38=7x) -y to both sides
38=7x-y
you have to move the 38 and y because if you moved the x value, than A becomes negative and it can't be in standard form
