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2 years ago

Heeellllllppppppppp?? anyonnneeee?

Mathematics

1 answer:

Aleonysh [2.5K]2 years ago

3 0

Answer:

It's no answer. This question is unsolvable

Step-by-step explanation:

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Annabelle owns a small business selling clothing. She knows that in the last week 56 customers paid cash, 26 customers used a de

frosja888 [35]

Answer

23/51

Step-by-step explanation:

The probability of the next customer paying with a debit or credit card is =23/51

5 0

1 year ago

In Exercise, find the derivative of the function. y = ln(3 + x2)

erastovalidia [21]

Answer: $\dfrac{2x}{3 + x^2}$

Step-by-step explanation:

We know the property of derivative: $\dfrac{d}{dx}(\log (x))=\dfrac{1}{x}$

Given function : $y=\ln(3 + x^2)$

Differentiate both sides with respect to x , we get

$\dfrac{dy}{dx}=\dfrac{d}{dx}(\ln(3 + x^2))$

$\Rightarrow\ \dfrac{dy}{dx}=\dfrac{1}{3 + x^2}\cdot\dfrac{d}{dx}(3 + x^2)$ [By Chain rule]

$\Rightarrow\ \dfrac{dy}{dx}=\dfrac{1}{3 + x^2}\cdot(0+2x)$

[Since $\dfrac{d}{dx}(a)=0$ , where a is scalar and $\dfrac{d}{dx}(x^n)=n(x)^{n-1}$ ]

$\Rightarrow\ \dfrac{dy}{dx}=\dfrac{2x}{3 + x^2}$

Hence, the derivative of the given function is $\dfrac{2x}{3 + x^2}$ .

5 0

3 years ago

PLESE HELP WITH ANSWER. rewrite the function in the given form

kirza4 [7]

s hard and too long I'm only of class 13

5 0

2 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers

Three tennis balls are packaged in a box as shown below. The box is 12.1 centimeters long, 3.5 centimeters wide, and 3.5 centime

grin007 [14]

The volume is 91.8cm³

7 0

2 years ago

Heeellllllppppppppp?? anyonnneeee?​

Heeellllllppppppppp?? anyonnneeee?