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solniwko [45]
4 years ago
9

What is a possible value for the missing term in the geometric sequence? 18, _, 8

Mathematics
2 answers:
sp2606 [1]4 years ago
4 0
13 because you do 18-8 and you get 10 and divide that by 2 and you get 5 then add 5 to 8 and you get 13 and subtract 5 from 18 and you get 13 as well. Hope that helps
jasenka [17]4 years ago
3 0
Since it's geometric, the ratio between the second and first term is equal to the ratio between the third and secons term.

So, x/18 = 8/x
x^2 = 144
So, x can be either 12, or -12
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Based on the dot plots predict whether the mean or median will be greater for each data set.
Reil [10]
Hi can you answer my question I am giving away 44 points
7 0
3 years ago
jessica put 4 tables together for the Pie day sale. Each table is 42 inches long. What is the total length of the tables express
kondaur [170]

Answer:

14 feet OR 168 inches

Step-by-step explanation:

4 tables multiplied by 42 inches equals 168 inches total

168 inches divided by 12 inches per feet equals 14 feet.

5 0
3 years ago
(a) Estimate the area under the graph of f(x) = 2 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right end
nirvana33 [79]
  <span>first, we are going to define variables as the following: 

a = 0 
a = π/2 
n = 4 rectangles 

Δx = [ b - a ] / n ------>Δx = [ π/2 - 0 ] / 4 = π/8 

right endpoints : 
sum( seq( 4 cos(x) * π/8 , x , 0+π/8 , π/2 , π/8 ) ) = 3.163065 underestimate 

left endpoints: 
sum( seq( 4 cos(x) * π/8 , x , 0 , π/2-(π/8) , π/8 ) ) = 4.733861 overestimate 

the reason because the actual estimate by integral as the following: 
π/2 
∫ 4cos(x) dx = 4 
0</span>
8 0
3 years ago
In the figure, PA and PB are tangent to circle O and PD bisects ∠BPA . The figure is not drawn to scale. For m
Mademuasel [1]

Angle AOC = 46°   Find angle BPO

We have congruent right triangles PAO and PBO, right angles A and B.

So AOC=BOC=46 degrees,

PBO is a right angle so BPO is complementary to BOC, so 42 degrees

Answer: 42 degrees

3 0
3 years ago
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n&#10;\\&#10;\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
4 years ago
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