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solniwko [45]
3 years ago
9

What is a possible value for the missing term in the geometric sequence? 18, _, 8

Mathematics
2 answers:
sp2606 [1]3 years ago
4 0
13 because you do 18-8 and you get 10 and divide that by 2 and you get 5 then add 5 to 8 and you get 13 and subtract 5 from 18 and you get 13 as well. Hope that helps
jasenka [17]3 years ago
3 0
Since it's geometric, the ratio between the second and first term is equal to the ratio between the third and secons term.

So, x/18 = 8/x
x^2 = 144
So, x can be either 12, or -12
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A population of rabbits triples every month.the population starts with two rabbits.how many rabbits are there after 3 month's
Tresset [83]
The answer would be 54. Because you start with 2.
2x3 = 6
6x3 = 18
18x3 = 54
Each month it triples so you continue
to add 3 to each result.
7 0
4 years ago
Altogether how many legs do 30 cows have
Tresset [83]

Answer:

A cow possess 4 legs.

So, 30 of them will have 4 × 30= 120 legs

Option 3

6 0
3 years ago
Read 2 more answers
As a fraction in simplest terms, what would you multiply the first number by to get the second?
Alinara [238K]

Answer:

22/25

Step-by-step explanation:

66/75 = 22/25

Input into equation to confirm

75 · 22/25 = 66

1650/25 = 66

66 = 66, so we're right

5 0
3 years ago
Please answer! I crossed out the ones you don’t have to complete.
Nina [5.8K]

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

a.a as a^{1+1}=a^2

b.b.b.b as: b^{1+1+1+1}=b^4

So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

4 0
3 years ago
Solve this pleaseeeee
Ivan

Answer:

-4 < n ≤ 5

Step-by-step explanation:

________________

7 0
3 years ago
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