Ask question

Ask question

All categories

3 years ago

10

Plzzzzz help meee!?!?!?!?

1 answer:

tamaranim1 [39]3 years ago

4 0

I would most likely go with answer D. but if this is incorrect i am truly sorry.

You might be interested in

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

3 years ago

33.366 divided by 6.7

andrey2020 [161]

Answer:

Step-by-step explanation:

33.366/6.7= 4.98

5 0

3 years ago

What is 90 by 25% decreased

viva [34]

Answer:

- 22.5

Step-by-step explanation:

Answer:

90 decreased by 25% = 67.5

Absolute change (actual difference):

67.5 - 90 = - 22.5

8 0

2 years ago

Read 2 more answers

The formula y = mx + b is called the slope-intercept form of a line. Solve this formula for m

Evgesh-ka [11]

Answer:

m = $\frac{y-b}{x}$

Step-by-step explanation:

Given

y = mx + b ( subtract b from both sides )

y - b = mx ( divide both sides by x )

$\frac{y-b}{x}$ = m

3 0

3 years ago

Please help :) I have no clue & math isn’t my strong subject.

melisa1 [442]

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

Solution:

Given line $y=\frac{4}{7} x+4$ .

Slope of this line, $m_1$ = $\frac{4}{7}$

$$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }$

$$m_2=\frac{-1}{m_1}$

$$=\frac{-1}{\frac{4}{7} }$

Slope of perpendicular line, $m_2=\frac{-7}{4}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$y-y_1=m(x-x_1)$

$$y-(-7)=\frac{-7}{4} (x-5)$

$$y+7=\frac{-7}{4} x+\frac{35}{4}$

Subtract 7 from both sides, we get

$$y=\frac{-7}{4} x+\frac{7}{4}$

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

To find the parallel line:

Slopes of parallel lines are equal.

$m_1=m_3$

$$m_3=\frac{4}{7}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$$y-(-7)=\frac{4}{7} (x-5)$

$$y+7=\frac{4}{7} x-\frac{20}{7}$

Subtract 7 from both sides,

$$y=\frac{4}{7} x-\frac{69}{7}$

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

7 0

3 years ago