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3 years ago

PLS HELP find the area of the shape below

Mathematics

1 answer:

Iteru [2.4K]3 years ago

8 0

Answer:

160

Step-by-step explanation:

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Layla used 0.482 gram of salt in her experiment. Maurice used 0.51 gram of salt in his experiment. Which pf the following amount

Sedaia [141]

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4 years ago

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What is 1000+52603+58964+5236809+968532-68972100 = ?

IRINA_888 [86]

Answer:

−62,654,192 is your answer

4 0

3 years ago

X/3/9=5/9 SOLLVE FOR X!!!!!!!

Zanzabum

Answer:

x = 15

Step-by-step explanation:

x/3/9 = 5/9

x : 3 : 9 = 5/9

x×1/3×1/9 = 5/9

x/27 = 5/9

x = 5×27/9

x = 5×3

x = 15

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4 years ago

In a triangle CMS angle C measure 63 degrees and angle M measures 47 degrees. wht is the measure of angle S?

muminat

Answer:

s=70

Step-by-step explanation:

all angles in a triangle add up to equal 180 degrees.

180-63-47=s

70=s

7 0

4 years ago

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is

anastassius [24]

Answer:

The rate of change of temperature is 1.29 degree Celsius per second.

Step-by-step explanation:

We are given the following information in the question:

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius where x and y are measured in centimeters.

$x = \sqrt{2+t}\\\\y = 5 + \displaystyle\frac{1}{14}t$

$T_x(4,6) = 8, T_y(4,6) = 4$

We have to find the rate at which the temperature is rising on the bug's path after 14 seconds.

At t = 14 seconds, we have,

$x = \sqrt{2+14} = 4\\\\y = 5 + \displaystyle\frac{1}{14}(14) = 5+1 = 6$

To find rate of change of temperature, we differentiate,

$\displaystyle\frac{dT}{dt} = \frac{dT}{dx}\frac{dx}{dt} + \frac{dT}{dy}\frac{dy}{dt}\\\\\displaystyle\frac{dT}{dt} = T_x(x,y)(\frac{1}{2\sqrt{2+t}}) + T_y(x,y)\frac{1}{14}\\\\At~ t = 14, x = 4, y = 6\\\\\frac{dT}{dt} = T_x(4,6)(\frac{1}{2\sqrt{2+t}}) + T_y(4,6)\frac{1}{14}\\\\\frac{dT}{dt} = 8\times \frac{1}{8} +4\times \frac{1}{14} = 1 + 0.2857 = 1.2857$

Thus, the rate of change of temperature is 1.29 degree Celsius per second.

7 0

3 years ago