Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
Answer:
.000167
Step-by-step explanation:
To get 1.67x10^-4 into standard from, we move the decimal to the left (the negative sign means to the left) 4 places. That means we need to add 3 zero's.
.000167
Answer:
b. 1/2
Step-by-step explanation:
lim (x -3)(x +2)
x-->-∞ ---------------
2x^2 + x +1
= lim (x^2 -3x +2x - 6)
x-->-∞ -----------------------
2x^2 + x +1
= lim (x^2 -x - 6)
x-->-∞ -----------------------
2x^2 + x +1
When we plug in x = -∞, we get indeterminate form.
Now we have to use the L'hospital rule.
d/dx (x^2 - x - 6) = 2x -1
d/dx (2x^2 + x + 1) = 4x + 1
Now apply the limit
lim (2x - 1) / (4x + 1)
x--->-∞
Here we have to degree of the numerator and the denominator of the same. In this case, if x --> -∞, we get the result as the coefficient of the leading term as the result.
According to the rule, we get
= 2/4
Which can simplified as 1/2
The answer is 1/2
Hope this will helpful.
Thank you.
Answer:
X = 3
Step-by-step explanation:
Hmm this ones tricky.....
