Given:
JK is tangent to a circle with center H
To find:
The length of HK.
Solution:
The image is attached below.
JK = 8 mi, HJ = 15 mi
JK is tangent to a circle.
The tangent is always perpendicular to the radius.
Therefore, m∠J = 90°
Using Pythagoras theorem:
HK² = JK² + HJ²
HK² = 8² + 15²
HK² = 64 + 225
HK² = 289
HK² = 17²
Taking square root on both sides.
HK = 17
The length of HK is 17 mi.
So to set this problem up lets understand it.
each percent is out of a whole (100%)
so the whole in this problem is 450 pounds
and to make 44% a usable number we move the percent sign two places over.
.44
to find out how many times .44 goes into 450 pounds we will multiply
(.44×450)=198 pounds
we can check our answer by dividing 198÷450
and getting .44 as our answer
Step-by-step explanation:
so, I assume the patio is a true rectangle.
the area of a rectangle is
length × width
in our case that means
1.3 = 5 × width
width = 1.3 / 5 = 0.26 ft
so, this is just a very narrow strip of 0.26ft × 5 ft.
I would not call that a patio ...
or was it a typo, and the area is actually 30 ft² ?
then we would have
30 = 5 × width
width = 30 / 5 = 6 ft
1/12 because you subtract 4 and 16 and you get 12
Answer:
but i cant see the question
Step-by-step explanation:
if not i would have helped
