Find the perfect square of 57600
1 answer:
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Answer:
Perimeter of ΔABC = 16.46 units
Step-by-step explanation:
By applying cosine rule (CAH) in the given triangle ADB,
cos(∠BAC) =
cos(55°) =
AB = 5.23 units
Since, ΔABC is an isosceles triangle
AB = BC = 5.23 units
AD = DC = 3 units [Perpendicular drawn from a vertex of an isosceles triangle is a perpendicular bisector of the opposite side]
Therefore, AC = AD + DC = 6 units
Now perimeter of ΔABC = AB + BC + AC
= 5.23 + 5.23 + 6
= 16.46 units
1. We have to prove that in a 45°–45°–90° isosceled triangle, the hypotenuse is times the length of each leg.
2. Since, triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, which states
But, in isosceles triangle it becomes
3. By combining like terms, we get
4. Now, we will determine the principal square root of both sides of the equation.
5. Dividing both sides of the equation by '2', we get
So,
6. So the hypothenuse c is times the length of each leg 'a'.