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2 years ago

8

Write the equation of the line that passes through the given points. (0,3) and (-17,1)

1 answer:

Zina [86]2 years ago

4 0

Answer:

the equation: y=2/17x+3

the slope: 2/17

Step-by-step explanation:

You might be interested in

Following a group of truck drivers and noting the number of miles traveled for one year refers to which type of statistical stud

maria [59]

Considering that the data is only noted and not changed, this is an example of an observational study.

<h3>What are observational and experimental studies?</h3>

Experimental study: In an experimental study, there is an intervention in a sample, and it's effect is studied.

Observational study: In an observational study, the sample is just analyzed, without any intervention.

In this problem, the data, which is the number of miles traveled, is only analyzed, no interventions are made, hence this is an example of an observational study.

More can be learned about observational studies at brainly.com/question/24321224

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6 0

1 year ago

Information on a sample of 362 college students is collected. The complete dataset is available at StudentSurvey. We see that 27

pishuonlain [190]

Answer:

So, we conclude that the best estimate for the difference in the proportion of smokers is 4.4%.

Step-by-step explanation:

We know that 27 of the 193 males in the sample smoke while 16 of the 169 females in the sample smoke.

We have the following proportion:

$27:x=193:100\%\\\\193x=27\cdot 100\\\\193x=2700\\\\x=\frac{2700}{193}\\\\x=13.9\%$

So we get that 13.9% of men smoke.

We have the following proportion:

$16:x=169:100\%\\\\169x=16\cdot 100\\\\169x=1600\\\\x=\frac{1600}{169}\\\\x=9.5\%$

So we get that 9.5% of women smoke.

We get: 13.9%-9.5%=4.4%.

So, we conclude that the best estimate for the difference in the proportion of smokers is 4.4%.

6 0

2 years ago

The half-life of a radioactive element is 130 days, but your sample will not be useful to you after 80% of the radioactive nu

gtnhenbr [62]

Answer:

We can use the sample about 42 days.

Step-by-step explanation:

Decay Equation:

$\frac{dN}{dt}\propto -N$

$\Rightarrow \frac{dN}{dt} =-\lambda N$

$\Rightarrow \frac{dN}{N} =-\lambda dt$

Integrating both sides

$\int \frac{dN}{N} =\int\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$\Rightarrow ln|N_0|=-\lambda .0+c$

$\Rightarrow c= ln|N_0|$

$\therefore ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$ .......(1)

$\frac{N}{N_0}=e^{-\lambda t}$ .........(2)

Logarithm:

$ln|\frac mn|= ln|m|-ln|n|$
$ln|ab|=ln|a|+ln|b|$

$ln|e^a|=a$

$ln|a|=b \Rightarrow a=e^b$
$ln|1|=0$

130 days is the half-life of the given radioactive element.

For half life,

$N=\frac12 N_0$ , $t=t_\frac12=130$ days.

we plug all values in equation (1)

$ln|\frac{\frac12N_0}{N_0}|=-\lambda \times 130$

$\rightarrow ln|\frac{\frac12}{1}|=-\lambda \times 130$

$\rightarrow ln|1|-ln|2|-ln|1|=-\lambda \times 130$

$\rightarrow -ln|2|=-\lambda \times 130$

$\rightarrow \lambda= \frac{-ln|2|}{-130}$

$\rightarrow \lambda= \frac{ln|2|}{130}$

We need to find the time when the sample remains 80% of its original.

$N=\frac{80}{100}N_0$

$\therefore ln|{\frac{\frac {80}{100}N_0}{N_0}|=-\frac{ln2}{130}t$

$\Rightarrow ln|{{\frac {80}{100}|=-\frac{ln2}{130}t$

$\Rightarrow ln|{{ {80}|-ln|{100}|=-\frac{ln2}{130}t$

$\Rightarrow t=\frac{ln|80|-ln|100|}{-\frac{ln|2|}{130}}$

$\Rightarrow t=\frac{(ln|80|-ln|100|)\times 130}{-{ln|2|}}$

$\Rightarrow t\approx 42$

We can use the sample about 42 days.

7 0

3 years ago

Solve for x 1/12=4x/3+5/3(x-7/4)

ziro4ka [17]

Answer:

x=1

Step-by-step explanation:

1) multiply the numbers

2) combine multiplied terms into a single fraction

3) distribute

4) combine fractions with common denominator

5) combine like terms

6) multiply all terms by the same value to eliminate fraction denominators

7) cancel multiplied terms that are in the denominator

8) multiply the numbers

9) add 35/4 to both sides of the equation

10) simplify

( add the numbers twice)

11) divide both sides of the equation by the same term

12) simplify

(divide the numbers, cancel terms that are in both the numerator and denominator, and last but not least move the variable to the left)

well and behold your answer is x=1

6 0

2 years ago

Find cos theta, please help!

mr Goodwill [35]

Answer:

21/29

Step-by-step explanation:

$\cos \theta = \frac{AC}{AB} = \frac{42}{58} = \frac{21}{29} \\$

5 0

2 years ago

Read 2 more answers