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3 years ago

HELPPPPP!!!!A formula for finding the perimeter of a rectangle is P = 2L + 2W. If you know the perim

Mathematics

1 answer:

insens350 [35]3 years ago

3 0

Answer:

W = P/2 - L

Step-by-step explanation:

WE need to make W the subject of

P = 2L + 2W

2W = P - 2L

W = ( P - 2L) / 2

or W = P/2 - L

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Ted and Alan are in a race to double their money. Ted feels he will win if he puts his $4,000 into a savings account offering 4.

siniylev [52]

Ted:
4,000 @ 4.5% interest compounded annually

Alan:
1,000 @ 6% interest compounded annually

Rule of 72: divide 72 by the compound annual interest rate

Ted: 72/4.5% = 16 years
Alan: 72/6% = 12 years

Alan will win. It will take 12 years.

8 0

2 years ago

Read 2 more answers

Picture of reflected trapezoid above the line

asambeis [7]

Answer:

which line!

x or y axis?

first image is over the x axis

second is over the y

Step-by-step explanation:

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2 years ago

Fill in the blanks with <, > or = sign. [-4] ______ [-8] [-100] _____0

steposvetlana [31]

Answer:

the first ones >

Step-by-step explanation:

the second ones <

4 0

2 years ago

Please help im really confused :(

pantera1 [17]

Answer:

a) π

b) 33.4

Step-by-step explanation:

C = πd

1) substitute 105 for C: 105 = πd

2) plug in approximate value of 3.14 for π: 105 = (3.14) d

3) isolate to solve for d: 105/3.14 = d

4) simplify: 105/3.14 ≈ 33.4

5 0

3 years ago

Historical data for a local manufacturing company show that the average number of defects per product produced is 2. In addition

charle [14.2K]

Answer:

The probability that there will be a total of 7 defects on four units is 0.14.

Step-by-step explanation:

A Poisson distribution describes the probability distribution of number of success in a specified time interval.

The probability distribution function for a Poisson distribution is:

$P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}, x=0,1,2,3,...$

Let X = number of defects in a unit produced.

It is provided that there are, on average, 2 defects per unit produced.

Then in 4 units the number of defects is, $(2\times4)=8$ .

Compute the probability of exactly 7 defects in 4 units as follows:

$P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}\\P(X=7)=\frac{e^{-8}8^{7}}{7!}\\=\frac{0.0003355\times2097152}{5040}\\ =0.1396\\\approx0.14$

Thus, the probability of exactly 7 defects in 4 units is 0.14.

8 0

3 years ago