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3 years ago

[ Will give brainliest! ]

Mathematics

1 answer:

algol133 years ago

3 0

The answer is C
If the two chords intersect each other, that means that they must both be diameters. That means that JL + NL has to be equal to KL + ML. Because they are both diameters, they both have to be equal to each other. The only choice that satisfies this condition is C where both of the diameters are 16 in long.

Hope this helps :)

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The sum of 13 divided by a number and that number divided by 13

7nadin3 [17]

Sum means add

the number is x

13 divided by a number is 13/x
the number divided by the number is x/13

so
$\frac{13}{x}+\frac{x}{13}$
also can be simplified to
$\frac{169}{13x}+\frac{x^2}{13x}$ or
$\frac{x62+169}{13x}$

translated it is $\frac{13}{x}+\frac{x}{13}$ where x is the number

5 0

3 years ago

WILL GRANT BRAINIEST IF CORRECT, PLEASE HELP!!

Yuri [45]

Answer:

Step-by-step explanation:

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8 0

3 years ago

For the equation, complete the solution. 7x + y = −18

Alex777 [14]

Answer:

x= - 18/7 - 1/7y, y

or if you are solving for y= -18-7x, x

( SEE OTHER IMAGE)

Step-by-step explanation:

See image below:)

8 0

3 years ago

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A student claims that 8^3 x 8^-5 is greater than 1. Explain whether the student is correct or not.

nlexa [21]

Remember:
a^m * a^n=a^(m+n)
a^-m=1/a^m

8³ x 8⁻⁵=8³⁻⁵=8⁻²=1/8²=1/64<1

Answer: the student is not correct, because 1/64<1, and 8³ x 8⁻⁵=1/64.

7 0

3 years ago

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is:

$\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|$

$\Delta t_{1/2} \approx 65.788\,days$

The approximate difference in the half-lives of the isotopes is 66 days.

4 0

3 years ago

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