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Mrrafil [7]
3 years ago
8

B eshv jeksbhveasjgvkjhsv shbjewkhbf hjkbmnf ksdbfnbdb vj nwehjfrnves hv

Mathematics
2 answers:
timurjin [86]3 years ago
6 0

Answer:

hdhshuwwiejbeb eeiiihe eubehwueub eiije

Step-by-step explanation:

the god tham answer

Alex_Xolod [135]3 years ago
4 0

Answer:

This is jibberish

Step-by-step explanation:

Just language please and thanks

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Musya8 [376]

t^2\dfrac{\mathrm dy}{\mathrm dt}+y^2=ty

Divide both sides by y^2:

\dfrac{t^2}{y^2}\dfrac{\mathrm dy}{\mathrm dt}+1=\dfrac ty

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\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{z-t\frac{\mathrm dz}{\mathrm dt}}{z^2}

so that the ODE is transformed to

z^2\dfrac{z-t\frac{\mathrm dz}{\mathrm dt}}{z^2}+1=z

z-t\dfrac{\mathrm dz}{\mathrm dt}+1=z

and assuming t>0,

\dfrac{\mathrm dz}{\mathrm dt}=\dfrac1t

The remaining ODE is separable:

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