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AlexFokin [52]
3 years ago
11

58​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the

number of U.S. adults who have very little confidence in newspapers is ​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four.
a) ​P(5)=
(b) ​P(x​≥6)=
​(c) ​P(x​<4)=
Mathematics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

.216165788

.582225057

.417774943

Step-by-step explanation:

We need to use a binomial distribution here

A.

10C5*.58⁵*(1-.58)⁵= .216165788

B.

I honestly think the fastest way to solve this is adding the probabiblity of exactly 6,7,8,9,10

which means we write

10C6*.58⁶*(1-.58)⁴+10C7*.58⁷*(1-.58)³+10C8*.58⁸*(1-.58)²+10C9*.58⁹*(1-.58)+10C10*.58¹⁰= .582225057

C.

To solve this just take the compliment of answer B

1-.582225057= .417774943

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The average THC content of marijuana sold on the street is 9.3%. Suppose the THC content is normally distributed with standard d
velikii [3]

Answer:

a) X \sim N(9.3,1)  

b) P(X>9.2)=P(\frac{X-\mu}{\sigma}>\frac{9.2-\mu}{\sigma})=P(Z>\frac{9.2-9.3}{1})=1-P(Z

c) The value of height that separates the bottom 75% of data from the top 25% is 9.9745.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(9.3,1)  

Where \mu=9.3 and \sigma=1

3) Part b

We are interested on this probability

P(X>9.2)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>9.2)=P(\frac{X-\mu}{\sigma}>\frac{9.2-\mu}{\sigma})=P(Z>\frac{9.2-9.3}{1})=1-P(Z

4) Part c

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.6745. On this case P(Z<0.6745)=0.75 and P(z>0.6745)=0.25

If we use condition (b) from previous we have this:

P(X  

P(Z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.6745

And if we solve for a we got

a=9.3 +1*0.6745=9.9745

So the value of height that separates the bottom 75% of data from the top 25% is 9.9745.  

8 0
3 years ago
Which expression correctly simplifies ... (see photo)
Anestetic [448]

Answer:

The last one

Step-by-step explanation:

FInd a common demominator which is 20 and multiply both so it turns into 4 19/20

8 0
2 years ago
Plz help me with my algebra
Rus_ich [418]
The answer is a(x)=x+3
3 0
3 years ago
Read 2 more answers
Help please and thanks!
IRISSAK [1]
Alright. It seems like the triangle that has the 45 degree angle with angles c & d is an isosceles triangle which meas two sides are equal.
If that is true, angle d would be 45. Add 45 and 45 together to get 90, which is angle c. The angle right across from c, a, will be 90 as well. Add 90 and 45 to get 135 and then do 180 - 135 to get angle b. Angle b should equal 45 as well. So adding each of the angles together, 90 + 45 + 90 + 45 = 360 

Your final answer is 360. 
8 0
3 years ago
In a statistics class, 10 scores were randomly selected with the following results (mean = 71.5): 74, 73, 77, 77, 71, 68, 65, 77
algol13

Answer:

Range: 12

Step-by-step explanation:

65, 66, 67, 68, 71, 73, 74, 77, 77, 77

Formula:

Range: highest value - lowest value = final answer

Range: 77 - 65 = 12

3 0
3 years ago
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