Answer:
The answers are A, B, C, F
Answer:
And we can use the following formula:
And replacing the info we got:
Step-by-step explanation:
We define two events for this case A and B. And we know the probability for each individual event given by the problem:
And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:
And for this special case we want to find this probability:
And we can use the following formula:
And replacing the info we got:
Answer:
(90)(7) ⇒ the error was multiplying 90 and 7.
Step-by-step explanation:
12(597) = 12(500 + 90 + 7)
= 12(500) + (90)(7)
= 6000 + 630
= 6,630
The part in bold shows where the error is. It was not correct to multiply 90 and 7.
The process was to proceed as follows:
12(597) = 12(500 + 90 + 7)
= 12(500) + 12(90) + 12(7)
= 6000 + 1080 + 84
= 7,164
Answer:
The statement is true about whether A and B are independent eventa is fourth option:
A and B are not independent events because P(A/B)=0.375 and P(A)=0.25
Step-by-step explanation:
Let A be the event that the person rides the bus to school, then:
P(A)=75/300
P(A)=0.25
Let B be the event that the person has 3 or more siblings, then:
P(B)=24/300
P(B)=0.25
P(A/B)=9/24
P(A/B)=0.375
Like P(A/B)=0.375 is different to P(A)=0.25 the events are not independent
Answer. Fourth option:
A and B are not independent events because P(A/B)=0.375 and P(A)=0.25
Let x = original price
Knowing that multiplying the original price and the discount is the discount price. We formulate:
x(1 - 0.40) = 179.94
x(0.60) = 179.94
x = 179.94/0.60
x = 299.9
That is about 300 of the original price.
