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Montano1993 [528]
3 years ago
6

Which statements are correct? Check all that apply.?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Answer:

(A) The rate of change is 5

(C) The rate of change is 4/1

(D) The plant grows 4 cm in 1 week

Step-by-step explanation:

just got it right on edge

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State University uses thousands of fluorescent light bulbs each year. The brand of bulb it currently uses has a mean life of 600
Ipatiy [6.2K]

Answer:

The test statistic is t = 2.5.

The p-value of the test is of 0.007 < 0.05, which means that the evidence supports the manufacturer's claim at the .05 significance level.

Step-by-step explanation:

Mean life of 600 hours. Test if it is more.

At the null hypothesis, we test if the mean is of 600 hours, that is:

H_0: \mu = 600

At the alternative hypothesis, we test if the mean is of more than 600 hours, that is:

H_1: \mu > 600

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

600 is tested at the null hypothesis:

This means that \mu = 600

Suppose 100 bulbs were tested and found to have a mean of 625 hours with a standard deviation of 100.

This means that n = 100, X = 625, s = 100.

Value of the test-statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{625 - 600}{\frac{100}{\sqrt{100}}}

t = 2.5

The test statistic is t = 2.5.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 625 hours, which is a right-tailed test, with t = 2.5 and 100 - 1 = 99 degrees of freedom.

Using a t-distribution calculator, this p-value is of 0.007.

The p-value of the test is of 0.007 < 0.05, which means that the evidence supports the manufacturer's claim at the .05 significance level.

4 0
3 years ago
Find the inverse of f(x)=1-5/2x
Varvara68 [4.7K]
F^-1(x)=1+5×2x
I hope this helps
3 0
3 years ago
Gavin, Colin and Dan share some sweets in the ratio 4:5:3. Gavin gets 20 sweets. How many sweets are there altogether?
Aliun [14]

9514 1404 393

Answer:

  60

Step-by-step explanation:

Gavin has 20/4 = 5 times as many sweets as his corresponding number of ratio units. The total number of ratio units is 4+5+3 = 12, so the total number of sweets is 5×12 = 60.

There are 60 sweets altogether.

_____

They are divided as ...

  • Gavin: 20
  • Colin: 25
  • Dan: 15
8 0
3 years ago
The temperature inside the lab refrigerator is at most 35 Fahrenheit used to represent the temperature in fahrenheit of the refr
wel

Complete question is;

Write inequalities to represent the situations below. The temperature inside the lab refrigerator is no more than 45 °F. Use t to represent the temperature (in °F) of the refrigerator.

Answer:

t ≤ 45 °F

Step-by-step explanation:

We are told to use t to represent the temperature (in °F) of the refrigerator.

We are also told that the temperature inside the lab refrigerator is no more than 45 °F.

For the temperature inside the refrigerator to be no more than 45 °F, it means the temperature should be either less than or equal to 45 °F

Thus means that t is less than or equal to 45 °F.

Thus, it can be represented in terms of inequality as;

t ≤ 45 °F

6 0
4 years ago
There are 6 white and 3 orange ping-pong balls in a brown paper bag. Two balls are randomly chosen. Enter your answers as fracti
Masteriza [31]

Answer:

a. 9

b. \mathbf{\frac{1}{3}}

c. \mathbf{\frac{1}{4}}

d. \mathbf{\frac{1}{12}}

Step-by-step explanation:

a. The total number of balls in the bag is

6 + 3 = 9

b. Let A denote the event that the 1st chosen ball is orange. Let B denote the event that the 2nd chosen ball is orange.

P(A) = \frac{\text{no. of orange balls in the bag}}{\text{Total no. of balls}} = \frac{3}{9} = \mathbf{\frac{1}{3}}

c. If the first choice is orange, (i.e A occurs) then there are 9 - 1 = 8 balls left in the bag with 3 - 1 = 2 orange balls.

P(B|A) = \frac{2}{8} = \mathbf{\frac{1}{4}}

d. Here we are required to compute P(B \cap A). We use the fact that

P(B|A) = \frac{P(B \cap A)}{P(A)} \implies P(B \cap A) = P(B | A) \times P(A) = \frac{1}{4} \times \frac{1}{3} = \mathbf{\frac{1}{12}}

4 0
4 years ago
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