All categories

3 years ago

Rationalize 1 plus root 2 divided by 1 minus root 2

Mathematics

1 answer:

yulyashka [42]3 years ago

6 0

The rationalized form of 1+ √2/1-√2 is -2√2-3

You might be interested in

Central and inscribed angle practice

Gelneren [198K]

Answer:

sorry

Step-by-step explanation:

I don't know what you want , do you want to know how to construct an inscribed angle or what

3 0

3 years ago

What is the sum of a 6-term geometric series if the first term is 21 and the last term is 1,240,029?

igor_vitrenko [27]

21 times x to the fifth (where x is the ratio between values) equals 1240029
1240029/21=59049
59049^(1/5)=9
so the values are 21, 21*9, 21*9^2, 21*9^3, 21*9^4, 1240029
the sum of these values is 1395030

5 0

3 years ago

Read 2 more answers

Simplify (3-3)/√3=0

zalisa [80]

Answer:

its 0 anyways lol

Step-by-step explanation:

4 0

3 years ago

You are pulling up an anchor while on a boat. You pull up the anchor at a rate of 0.5 feet per second. After 6 seconds, the anch

LekaFEV [45]

Answer:

the answer is 19 but I feel like it wrong hope it helps

5 0

3 years ago

Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

3 years ago