First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
Answer:
It has no solution because the two lines would never meet since they have the same slope of -3
Answer:
∠y = 62.5°
∠x = 27.5°
Step-by-step explanation:
z is right angle. ∠z = 90°
∠x = ∠y - 35
∠x + ∠y + ∠z = 180 {Angle sum property of triangle}
y - 35 + y + 90 = 180
y + y - 35 + 90 = 180 {Combine like terms}
2y + 55 = 180
2y = 180 -55 {Subtract 55 from both sides}
2y = 125 {Divide both sides by 2}
y = 125 /2
∠y = 62.5°
∠x = 62.5 - 35 = 27.5°
Answer:
0 People initially had the cold.
6 People will have it after 2 days.
Step-by-step explanation:
To find out how many people had it initially, plug 0 in for x (implying 0 days later.)
C= 1*3(0)
C= 1*0
C=0
Nobody had the cold initially.
To find out how many people had it after 2 days, plug 2 in for x. (implying 2 days later.)
C= 1*3(2)
C= 1*6
C=6
Therefore 6 people had the cold after 2 days.
I hope this helps!