Find the solution to the systems of equations using the elimination method.
2 answers:
X=-2/3y+11/3
x=-3/5y+14/5
Answer:
x = 1 ; y = 3
Step-by-step explanation:
5(2x + 3y = 11)
2(5x + 3y + 14)
(distribute)
10x + 15y = 55
10x + 6y = 28
(subtract)
9y = 27
(divided 9 to both sides)
9 divided by 9 cancels out and 27 divided by 9 = 3
so..
y = 3
now, using any equation, (i’ll be using 2x + 3y =11) plug in the y value to find the x value
2x + 3y = 11
2x + 3(3) = 11
(multiply 3 x 3)
2x + 9 = 11
(subtract 9 from 9 and 11)
2x = 2
(divide 2 from both sides)
2 divided by 2 = 1
therefore...
x = 1
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Evaluate 2x − 2 for x = 0, x = 1, and x = 2. Question 1 options: A) −1, 0, 2 B) −1, 1, 2 C) 0, 1, 2 D) 1, 2, 4
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The value of x in 2^x - 2 when x = 0, x = 1 and x = 2 are -1, 0 and 2 respectively. option A
<h3>Algebra</h3>
2^x - 2
when x = 0
2^x - 2
= 2^0 - 2
= 1 - 2
= -1
when x = 1
2^x - 2
=2^1 - 2
= 2 - 2
= 0
when x = 2
2^x - 2
= 2^2 - 2
= 4 - 2
= 2
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