Answer:
1. In triangle ABC,
AC = a = 10, BC =b= 7 and ∠ C = 90°
By cosine law,
Now, by the law of sine,
2. In triangle ABC,
∠B = 30°, AB=c=10 and ∠C = 90°
∠A = 180°-(30+90)°=60°
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By Pythagoras,
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1 answer:
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Answer:
Speed of plane in still air = 825 km/h
Step-by-step explanation:
Given:
Speed of plane with the wind is 145 km/h faster than what it would have with still air.
Speed of plane with wind = 970 km/h
To find speed of plane in still air.
Solution:
Let speed of plane in still air be = km/h
Thus speed of plane with wind would be given as = km/h
Speed of plane with wind is given =970 km/h
So, we have:
Solving for .
Subtracting both sides by 145.
∴ km/h (Answer)
Thus, speed of plane in still air = 825 km/h
This is the answer
Hope it helped
