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LUCKY_DIMON [66]
3 years ago
8

How many books about animal the bookstore have?

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

9+10 =21!

Step-by-step explanation:

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$600 - $40 = $560

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this means he can have up to a total of 22 people at his party

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I love sharks! In fact, before I became a statistician, I wanted to be a marine biologist specializing in shark research (I even
Ad libitum [116K]

Answer:

Null hypothesis: \mu \leq 15

Alternative Hypothesis: \mu >15

We have enough evidence to reject the null hypothesis at 10% level of significance.

Step-by-step explanation:

1) Data given

n =44, representing the sample size

\bar X=15.6ft represent the sample mean for the length of great white sharks

s=2.5ft represent the sample standard deviation for the  length of great white sharks

\alpha =0.1 significance level for the test

2) Formulas to use

On this case we are intereste on the sample mean for the  length of great white sharks, and based on the paragraph the hypothesis are given by:

Null hypothesis: \mu \leq 15

Alternative Hypothesis: \mu >15

since we have n>30 but we don't know the population deviation \sigma so we will can use the t approximation. The sample mean have the following distribution

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

Based on this the statistic to check the hypothesis would be given by:

t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}

Replacing the values given we have:

t_{calc}=\frac{15.6-15}{\frac{2.5}{\sqrt{44}}}=1.592

We can calculate the degrees of freedom with:

df=n-1=44-1=43

With \alpha and the degrees of freedom we can calculate the critical value, since \alpha=0.1 we need a value from the t distribution with 43 degrees of freedom that accumulates 0.1 of the area on the right or 0.9 of the area on the left.

We can use excel, a calculator or a table for this, calculating this value we got:

t_{(43,critc)}=1.302

Since our calculatesd value was t_{calc}=1.592>t_{crit}, we can reject the null hypothesis at 0.1 level of significance.

Other way in order to have a criterion for reject or don't reject the null hypothesis is calculating the p value, on this case based on the alternative hypothesis the p value would be given by:

p_v=P(t_{(43)}>1.592)=0.0594

So then p_v so we have enough evidence to reject the null hypothesis at 10% level of significance.

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4 years ago
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