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Anna11 [10]
2 years ago
6

First drop down : 1. Cylinder 2.sphere

Mathematics
2 answers:
Hunter-Best [27]2 years ago
8 0

Answer:

Below.

Step-by-step explanation:

To find the volume of the silo find the volum of the hemisphere with radius of 15 feet and add the volume of the cylinder with a radius of 15 feet and a height of (100 - 15) = 85 feet.

The total volume = 1/2 * 4/3 π (15)^3  + π (15)^2 * 85

= 67151.5 ft^3.

pogonyaev2 years ago
8 0

Step-by-step explanation:

find the volume of a sphere with a radius of 15 ft and divide by 2 (because there is only half a sphere on top of the silo).

then add the volume of a cylinder with a radius of 15 ft and a height of 85 ft (because we need to deduct the radius of the sphere from the total height to get the height of the cylinder itself).

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Laura has 30 cupcakes she wants to give each friend 1/6 of her cupcakes how many cupcakes will Each friend get
sdas [7]

Answer:

5 cupcakes

Step-by-step explanation:

=1x 30/ 6

=5

I hope it helps

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7 0
3 years ago
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The length of a rectangle is 1 foot less than twice the width. If the area is 45 ft2, find the length and width.
STatiana [176]
A) Width = 9/2, length = 10

Rectangle area = length(l)x width(w)

9/2 = 4.5

4.5(l) x 10(w) = 45ft
8 0
3 years ago
Is there an ordered pair solutions to <br> -3x+3y=4 and <br> -x+y=3 ????
elixir [45]
Y=x+3
-3x+3(x+3)=4
-3x+3x+9=4
9=4
Since this statement is false, there are no ordered pair solutions to this problem.
8 0
3 years ago
Help me ASAP for this question
ivann1987 [24]

Answer: Y= 2x

Step-by-step explanation:

1 x 2 = 2

3.4 x 2 = 6.8

5 x 2 = 10

7 x 2 = 14

So. Y = 2x

4 0
3 years ago
In a G.P the difference between the 1st and 5th term is 150, and the difference between the
liubo4ka [24]

Answer:

Either \displaystyle \frac{-1522}{\sqrt{41}} (approximately -238) or \displaystyle \frac{1522}{\sqrt{41}} (approximately 238.)

Step-by-step explanation:

Let a denote the first term of this geometric series, and let r denote the common ratio of this geometric series.

The first five terms of this series would be:

  • a,
  • a\cdot r,
  • a \cdot r^2,
  • a \cdot r^3,
  • a \cdot r^4.

First equation:

a\, r^4 - a = 150.

Second equation:

a\, r^3 - a\, r = 48.

Rewrite and simplify the first equation.

\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}.

Therefore, the first equation becomes:

a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150..

Similarly, rewrite and simplify the second equation:

\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}.

Therefore, the second equation becomes:

a\, r\, \left(r^2 - 1\right) = 48.

Take the quotient between these two equations:

\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}.

Simplify and solve for r:

\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}.

8\, r^2 - 25\, r + 8 = 0.

Either \displaystyle r = \frac{25 - 3\, \sqrt{41}}{16} or \displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}.

Assume that \displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}. Substitute back to either of the two original equations to show that \displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75.

Calculate the sum of the first five terms:

\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}.

Similarly, assume that \displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}. Substitute back to either of the two original equations to show that \displaystyle a = \frac{497\, \sqrt{41}}{41} - 75.

Calculate the sum of the first five terms:

\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}.

4 0
3 years ago
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