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podryga [215]
2 years ago
8

A standard deck has 52 cards consisting of 26 black and 26 red cards. Three cards are dealt from a shuffled deck without replace

ment. Let A=first card red and B=second card red. Are A and B independent? Explain why or why not.
Mathematics
1 answer:
Allisa [31]2 years ago
8 0

They aren't independent since the probability uses all the cards in the deck

So at the first deal we have the chance of 26/52 of getting a red card, at the second deal we have the chance of a 25/51 of getting another red card, so they aren't independent

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Write the equation of a line in slope intercept form of a line that has a slope of 5 and a y
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Solve for z -9(d+z)=-2z+59
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Read 2 more answers
Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i
Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) \frac{20i+21}{29}

(c) i

Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

(b) We have given expression \frac{5-2i}{5+2i}

After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

5 0
3 years ago
Rachel can buy licorice sticks for $0.75 and cherry candies for $0.50 and has a budget of $25 if her expenses are represented by
likoan [24]
You can buy 50 of the cherry candies with all of the 25$ because you do 25 divided by 0.50 and get 50 and then if you would like to check that do 50 x 0.50 and you will still get 25$
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