Let l, t, b represent the numbers of lions, tigers, bears, respectively.
2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals
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The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
8 plus 3 is 11, 15 minus 11 is 4
Complete question :
Edward bought 3 packages of hot dogs with 8 hot dogs in each package.He also bought 3 bags of hot dog buns 4 in each bag. Six people were hving lunch at his home, including eddward.How many hot dogs with bns could each of them have>
Answer:
4 hot dogs and 2 hot dog buns each
Step-by-step explanation:
Number of packages = 3
Number of hotdog package = 8
Total number of hotdogs = 8 * 3 = 24
Hot dog buns = 4 per bag
Buns = 4 * 3 = 12 buns
Hence the 6 could each have :
Hotdogs = 24 /6 = 4
Buns = 12 /6 = 2
4 hot dogs and 2 hot dog buns each
You can't solve one equation with 2 variables. You always need as many equations as there are variables. At most you can rewrite it in terms of y:
5y = 15 - 3x
5 = 3 - 3/5x