Question:
Approximate log base b of x, log_b(x).
Of course x can't be negative, and b > 1.
Answer:
f(x) = (-1/x + 1) / (-1/b + 1)
Step-by-step explanation:
log(1) is zero for any base.
log is strictly increasing.
log_b(b) = 1
As x descends to zero, log(x) diverges to -infinity
Graph of f(x) = (-1/x + 1)/a is reminiscent of log(x), with f(1) = 0.
Find a such that f(b) = 1
1 = f(b) = (-1/b + 1)/a
a = (-1/b + 1)
Substitute for a:
f(x) = (-1/x + 1) / (-1/b + 1)
f(1) = 0
f(b) = (-1/b + 1) / (-1/b + 1) = 1
Answer:
Option (D)
Step-by-step explanation:
Kevin delivers newspaper in his town and earns an amount represented by a linear equation,
y = 30x + 18
Here, y = total earnings
x = number of houses he delivers the newspaper
If he doesn't deliver any newspaper on a certain day, (x = 0)
Then total earnings, y = 30(0) + 18
y = 18 cents
Therefore, a certain amount of 18 cents will be paid even if he doesn't deliver any newspaper on a certain day.
Option (D) is the correct option.
1/2 = 40kg
1/5 = 22kg
1/2 = 5/10
1/5 = 2/10
3/10 is the difference between 18kg.
This means 1/10 of the box filled with apples is 6kg.
40 - (5 x 6) = 10kg. The box weighs 10kg alone.
All real numbers or is it multiple choice
Answer:
1050, 1200, 2550 and 5100.
Step-by-step explanation:
If the first number is x then the second is x + 1/7x.
The third = x + x + 1/7x + 300 and the fourth = x + x + 1/7x + x + x + 1/7x+ 300 + 300.
So our equation is:-
8x + 4 * 1/7x + 900 = 9900
60/7 = 9000
60x = 7*9000
x = 1050.
Therefore the 4 numbers are 1050, *1/7*1050 = 1200, 2550 and 5100.
