Subtract 4<span> from both sides
</span><span><span>y−4>−2x</span>
<span>Divide both sides by -2
</span>
x>-y-4/2
Question 2 - y>x-4
Add 4 to both sides
<span><span>y+4>x
Switch sides
</span>
<span><span>x<y+4</span><span>
</span></span></span>
</span>
3x=4y
x+y=21
x = 21-y
3(21-y)=4y
63-3y=4y
63=7y
y=9
x+y=21
x+9=21
x=12
answer is (12, 9)
Answer:
Step-by-step explanation:
You need to first find what x equals before you can solve the equation.
Ok so we need to set the bottom to 0 to find the vertical asympyotes. This becomes x^2 - 4 = 0. Since we're talking about asymptotes, i'll assume you can solve basic equations. Solving for x and you get x = ±2. This means the vertical asymptotes are at ±2. To solve for horizontal asymptotes you take the limit as x goes to ±∞. Either way you end up with ±∞/∞. Now this isn't 1 because they grow at different rates. You differentiate both the top and bottom(L'hopital) and you get 6x/2x which becomes 3. This means the horizontal asymptote is at y = 3.