Simplify the expression. 4x^10y^-3/12x^-2y

Which of these polynomials will make the following equation true

Amanda [17]

Poop I think good luck but it’s b x2-
512

4 0

3 years ago

Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the

BigorU [14]

The average travel time is simply the mean travel time between the given points

The average time that it takes for the car to travel the first 0.25m is 2.23s.
The average time to travel just between 0.25m and 0.50m is 0.9s.
Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

(a) The average time to travel the first 0.25m

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

$Time = \frac{2.24s + 2.21s + 2.23s}{3}$

$Time = \frac{6.68s}{3}$

$Time = 2.23s$

(b) The average time to travel just between 0.25m and 0.50m

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

$Time = \frac{3.16s + 3.08s + 3.15s}{3}$

$Time = \frac{9.39s}{3}$

$Time = 3.13s$

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

$Average = 3.13s - 2.23s$

$Average = 0.9s$

(c) The velocity in the second 0.25m section

The distance and time are:

$Distance = 0.25m$

$Time = 0.9s$

So, the velocity is:

$Velocity = \frac{Distance}{Time}$

This gives

$Velocity = \frac{0.25m}{0.9s}$

$Velocity = 0.28m/s$

Read more about distance, velocity and time at:

brainly.com/question/4931057

6 0

3 years ago

There is a 4-foot fence that surrounds your backyard. The fence casts a shadow that is 5 feet long. If you are 6 feet tall and s

Strike441 [17]

My shadow would be 7 feet tall.

Since I am standing next to the fence, then whatever difference its actual height and its shadow has, will be the same difference of my shadow to my actual height.

fence: Actual height - 4 ft ; Shadow height - 5 ft; difference - 1 ft
me : Actual height - 6 ft : Shadow height - ? ; difference - 1ft

Shadow Height - Actual Height = 1 ft
Sh - 6ft = 1ft
Sh = 1ft + 6ft
Sh = 7ft

3 0

3 years ago

Find the focus. y= -1/12 (x)² - 6

jolli1 [7]

Answer:

$\Large \boxed{\sf\ \ (0,-9) \ \ }$